# HS1 - Adams Russell Homework 1 Due midnight Inst Opyrchal H 1 This print-out should have 9 questions Multiple-choice questions may continue on the

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Unformatted text preview: Adams, Russell Homework 1 Due: Sep 12 2006, midnight Inst: Opyrchal, H 1 This print-out should have 9 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. The due time is Central time. 001 (part 1 of 1) 10 points Convert the volume 13 . 2 in . 3 to m 3 , recalling that 1 in. = 2.54 cm and 100 cm = 1 m. Correct answer: 0 . 000216309 m 3 . Explanation: Basic Concept: Unit Conversion Solution: Convert the units from English units to SI units: V = 13 . 2 in . 3 2 . 54 cm 1 in 3 1 m 100 cm 3 = 0 . 000216309 m 3 . keywords: 002 (part 1 of 1) 10 points A person walks 21 m East and then walks 37 m at an angle 37 North of East. What is the magnitude of the total dis- placement? Correct answer: 55 . 2366 m. Explanation: The total displacement is the vector sum of the two displacements, so R x = R a + R b cos = 21 m + 37 mcos37 = 50 . 5495 m R y = R b sin = 37 msin37 = 22 . 2672 m The final displacement is R = q R 2 x + R 2 y = q (50 . 5495 m) 2 + (22 . 2672 m) 2 = 55 . 2366 m . keywords: 003 (part 1 of 1) 10 points A particle undergoes two displacements. The first has a magnitude of 163 cm and makes an angle of 126 . 3 with the positive x axis. The resultant displacement of the two displace-...
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## This note was uploaded on 04/03/2009 for the course PHYS 111 taught by Professor Moro during the Spring '08 term at NJIT.

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HS1 - Adams Russell Homework 1 Due midnight Inst Opyrchal H 1 This print-out should have 9 questions Multiple-choice questions may continue on the

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