hw10solutions

hw10solutions - Phys 214 Spring 2008 HW10 Solutions 1...

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Unformatted text preview: Phys 214, Spring 2008: HW10 Solutions 1. YF (Discussion) Question 35.7 Given d=25 cm. Red light has a wavelength of ≈ 660 nm. Recall that y max = R mλ d , and therefore the distance between two maxima or minima on the screen is Δ y = R λ d . Δ y should be large enough for our eyes to resolve in order for us to observe an interference pattern. If we can’t resolve the maxima the maxima and minima, we will just see dim light hitting all of the screen. Given the values above, λ / d is on the order of 10- 6 (making Δ y ∼ microns when R = 1 m) , so we won’t be able to see the pattern unless R is very big. try out this Java applet: http://surendranath.tripod.com/Applets/Optics/Slits/DoubleSlitID/DblSltIntDifApplet.html 2. YF Exercise 35.10 Given: λ = 502 nm, R=1.20 m, and y 20 = 10.6 mm. We can find d with Equation 35.6 d = R m λ y m = 1.20 m 20 ( 502 × 10- 9 m ) 10.6 × 10- 3 m = 1.14 mm 3. YF Exercise 35.23 Given: d=0.260 mm, R=0.700 m, λ =660 nm, and I o at θ = 0 ....
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This note was uploaded on 03/31/2009 for the course PHYS 214 taught by Professor Thorne during the Spring '08 term at Cornell.

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hw10solutions - Phys 214 Spring 2008 HW10 Solutions 1...

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