121homework 1

# 121homework 1 - Felder Jacob – Homework 1 – Due noon...

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Unformatted text preview: Felder, Jacob – Homework 1 – Due: Sep 12 2006, noon – Inst: Vitaly 1 This print-out should have 6 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. The due time is Central time. 001 (part 1 of 2) 10 points Consider three force vectors ~ F 1 , ~ F 2 , and ~ F 3 . The vector ~ F 1 has magnitude F 1 = 50 N and direction θ 1 = 120 ◦ ; the vector ~ F 2 has mag- nitude F 2 = 25 N and direction θ 2 =- 110 ◦ ; and the vector ~ F 3 has magnitude F 3 = 18 N and direction θ 3 = 33 ◦ . All the direction an- gles θ are measured from the positive x axis: counter-clockwise for θ > 0 and clockwise for θ < 0. What is the magnitude F of the net force vector ~ F = ~ F 1 + ~ F 2 + ~ F 3 ? Correct answer: 34 . 8922 N. Explanation: In components, each force vector is F 1 ,x = F 1 × cos θ 1 =- 25 N , F 1 ,y = F 1 × sin θ 1 = 43 . 3013 N , F 2 ,x = F 2 × cos θ 2 =- 8 . 5505 N , F 2 ,y = F 2 × sin θ 2 =- 23 . 4923 N , F 3 ,x = F 3 × cos θ 3 = 15 . 0961 N , F 3 ,y = F 3 × sin θ 3 = 9 . 8035 N , and therefore the net force is F x = F 1 ,x + F 2 ,x + F 3 ,x =- 18 . 4544 N , F y = F 1 ,y + F 2 ,y + F 3 ,y = 29 . 6125 N ....
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121homework 1 - Felder Jacob – Homework 1 – Due noon...

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