BME311_midtermexamples

# BME311_midtermexamples - BME 311 Neiwork Them:r Midterm#1...

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Unformatted text preview: BME 311 Neiwork Them):r Midterm #1 Regular Exam (time: 129 minutes. total score 904-10 points} Name: . \$319.59: Question 1 [15 Quinta] For the bridge circuit shown In the following ﬁgure. R1. R2, R3, R0 and i, ere known parameters. (a) Determine the Thevenin equivalent circuit 5+5 (b) Find the load R; for maximum power transfer: 32 (c) Find the maximum power absorbed by the load. '5 {3 ‘RI 0.3615) ﬁgie+e4 ‘99.ng 91211—3) : O Lark. i.&.l§+ﬁgn.;rReLa TRqLQ- R115, 5:: Rh ISﬁEIfEa) :[AILR-i'i'ﬁg‘i‘ﬁg-HLT) L9“: Is Ciewtﬁz) E 1+R2+EB+RH L&R#m2‘IS\RQ-UTH:O "-9) VT“: ‘LQEQTCLQ‘ISBED‘ . Re“: Is R1 Chasm Liar New). _ L63 Pm: Vw? : :81 (KIRHLRZEBBL [TKTH- Li LRJHE 33LR2+R1+3LRITR2TR3feLa 7—3;“. -_ .'._.Z"I; ' ""- BME311NaMorkTheo|y Mime rm #1 Regular Exam (than: 120 militias. total mo 901-111 M) —_————————*—_______________ n Find the Thevenln equivalent circuit for the output terminals of the circuit shown. u...- __. .,_..,. . ‘_"""". I 6"“ ‘Si +31 ""10 4 «gig/”A hull/'qu'l. LEBTC’val/ll- . ._ “L1: 3&3 3:01—79? L: CUQ‘i-Q 1'5 (In) +5LQEO .' . 4- . d; -?>)+'6C54Lab+ﬁa=o*f” ”*1"- a 4519‘: '3) -'- “:1: 3/943 M1“ 6 La TBIQ‘BLQ Nab =_C._>_ Uab:vm : (3 x 2% +5"L’5—%)'+ 5L3}? Vm 18V (6) Ali | _ __ _ (0) John X.J. Zheng. mm BME 311 Newark Theory Midterm #1 Regular Exam (time: 120 minutes. 1013! score SOHO bouts) 3 10 oints Using nodal analysis. dan‘va and put in matrix form the equations for the node voltages of the following circuit. WHY. ecyﬁor BMW +0 cagfr odiﬁeweﬁr bui‘ ‘(Oxvfeo‘f msww. BME 311 Network Theory M Mann #1 Regular Exam (ﬁma: 120 minutes. total more 90“!!! points) A certain unknown circuit has {he l-v dqaradéﬁsﬁc 3M mtﬁiEhm information given in the H! plot. determine the Thevenin and the Norton equivalent cirwils of the unknown circuit. BME 311 Network Theory Midterm #1 Regular Exam (time: 120 m’a'iutee. tots were com points) _—__—_—___ W Ll‘fDm’rs for male Wt . The following circuit was built by 3 rec named lsmelov who did not take BME 3 1. V, and V, are batteries with the voltage and polarity as indicategﬂln the QIE-Slﬂ- _ l (a) What is wrong with lemalov’e circuit? KV L Lib-hot wheg‘ied. Mo want-a , ' _ I (b) lemalov notices that the batteﬂas were getting warm and that they did not really last that long. Please explain to Ismelov why this happens. WWW (Dec {52) Qﬂbtétence- .1“... . --._—‘_1-1_--r_- .—'—---r-«-__ _‘r‘ .‘ (d) By assuming that each battery has an internal resistance R.= Ea drew the circuit to include the intemel resistance of the batteries. F}: 5.12. (tug 9 (e) Calculate the power dissipated in each batter-y. '.. ﬁlial-”1‘13 7""(3 mil-'bﬁarwé M'Z'HE: 11;: 41/595 Bug—[mm 35 5ir+lerans tam: hymn . ‘ . L'Q E. (f) Galadateyepowerdteeapatedln R... . _ . . 135\$: Eli”; :: yaw as - - F." -- 28.2w - "J. ._ ‘J _.' - .c.--I . 1r” I ' ww- . T... . BME 311 Network Theory Midterm #1 Regular Exam (time: 120 minutes. total score 90H 0 poinie) ——~———____________ uestl 6 15 ohm I It' IS desired that the power delivered to the heater by the balance of the circuit as indicated' Is a maximum I’hrmmm Power ‘W‘W‘ﬁ‘?’ R-fpﬁ p-L‘i ‘5 9507., ‘ "Je' __,_ f D‘ r 3:43;? loJL ”an R'Hﬂ’ fad +Ioo a; 2+1: "NSOJ’L eiL’ '” (b) What' Is the mexrmum powar disei ated by the heater? Va; Um: ' ' 4 W W PM ‘ Tm = Mo = anew 4‘ a 3- MemszDQDi) " 80 i 0_ Ho‘— [(341] {c} Which source {’(V, or 1,) delivers most of the power to the heater? mama "szwrasﬁ'im THWI Fehmeryr 28. 2007 Page 6 of9 .1,»- '-r' iiaiiaE-.3'11Neiworsz‘moory Midiarmm Regular Exam (ﬂme: 120 minutes. total score 9mm points) 992mm (Dalmatia-the pmr dissipated in each resistor in the following circuit. 05‘. U1.“ [9 +40). " 4'50 1'0 BME 311 Network ‘t’l'mz-on.r ' Midterm #1 Regular Exam- (time: 120 minutes. total score 904-10 points} —-———_____.—__—_— Question 8 {10 Quinta! Given a mm an internal resistance of RM determine its effect when measuring the voltage across R; In the fotlowing ﬁgure. List equations and describe concepts to support your reasoning. L....-..-.. -nnau. I... .- n..-___ _ _..__....-....__ W149i we, Want; to manna 1'9 UR.“ HOWeUey r 1%,“: 55753;"? tam , rte-termini reéTﬁ—faﬁﬁﬂ. f 'R‘ L2‘ 1 W ‘V5 G— 71975 Scam/J & ”W? ”W rem-9:0 f QLE . Qw— mn"; J ismse___:2f’_fii€m/ W ”a ’2“ U121: R3 -Us L p; P—h k .u, . - thyme. PLP‘W‘ ' 1/ IL Q; + M mm 5 w” (0 animal—5 JHM“ Vejj‘zqﬁ) , ‘ Uol 'V‘ '7 ll _,_,_r BME 311 Network Theory Midterm #1 Regular Exam aim: 120 minutes. total smegma-"IO points) Find the input impedance Yr oftha circuit shown below. You mustehow your mrl'c-zand explain Bonus Quostlgg [10 ﬂing) . clearly any assumptions you make. Note that all branchés have t'h'a‘idenﬁcel impedance. ‘l’éh Com dinning}. 41¢]; family/gm m xii/ﬁlrfohsz- Lava/ﬂ If 2min hall/«P. W \LJI‘L am} answer, you Wf/ have M W716. y Hx {x 4‘ 6 (5 arr”: 6.1L"! "Hﬂ‘l‘j Fnlvlﬂhn J mﬁ— 6‘5 ’7‘“,va 3‘) ’5 WM . Wa Com OSSMM with? “W095 ”“4” “’3 {ls—£53“ fifﬁ'O/J/{lng CWquo {new male A -+o B..TS IA. I Aéswnﬂ When 7%- waM awn/é: 411109, T—{ wﬂ/ Jeanie. ran-fa - I ’5’ 73A each. At more), a: W Le (was! We 1:71 earmand W F ' ' "6) John XJ. Zheng. UTAuslln cw? Aeme .3" [A V'IGCIZ 63. ...
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