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Statics Exam 2

# Statics Exam 2 - Name ”F7 STATICS ENGR 2050 — SPRING...

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Unformatted text preview: Name: ”F7 STATICS: ENGR 2050 — SPRING 2008 EXAM 2 FEBRUARY 27, 2008 Instructions: 1. Write your name at the top of every page. 2. Pay attentionto what the question is asking. 3. Show all your calculations; draw BRIEF pictures if you need to; state any assumptions. 1. (30 pts) The crate shown is supported by three cables. Determine the weight of the crate, knowing that the tension force in cable AB is 3 kN. {A6 .5 P -v 2 M 1;” TM) J w _.> W .4 .5 M 77%— 5 (vovlull ~054Mb -(.,44t+24J-i09n) TA; {le 95:34:35“:— cronowﬁlml' 1(0 wolf L l . 744/013} “\$4710; _, .s M , .4 4 i '6” T49= [1M1 o.?>i. +i.z' c054“) =Q.§iﬁ§lﬁpl:+°ﬂ7qun’b 4-3904 limit) 1(0.8m72+ll-Zw7l+(-054M1 L " :3 ’— 1’ ‘J L: 12- "Zia-4).- —i,++‘"+0>lqgl‘*‘0‘ O > incl 1" ‘0", ‘__> “M. Eta-4): 2.4””.oaesz4lﬁclv0.17"ztz.’i7z)'lw‘ ‘0 a d " UV 75:2) ‘- -l.08'”‘+o,+*20<a Haul-0330‘» (2.1%“):0 ﬁmﬂmr / 944195} . M+o Zmﬁan. 772‘ 4m+o,8814~(4'-3°° l“)+ off? 32C2I772’W) — W ‘0 .4 We =»[Wl= 8.407” =» W=-8-4°" J Page 1 of 3 Name: k2 STATICS: ENGR 2050 — SPRING 2008 EXAM 2 , FEBRUARY 27, 2008 2. (35 pts) The force F = 30 N acts on the bracket as shown. Determine the moment of the force about the a—a axis of the pipe. .5 r1 :Q‘Sieﬂgjtullt) A __‘ __\ j \Mara\‘ um'trxi' o \ D 400% 0"” HS’OM is“ 15" Zn?!” 1‘ 2 0’1 [rioomwzrf—(5‘09”)1+0=437/“Wm: 427i M _> :7 [\AQ,&= )Wa’a\&jo-a> :7 Page 2 of 3 Name: VX if _._________.___ STATICS: ENGR 2050 - SPRING 2008 EXAM 2 . FEBRUARY 27, 2008 4. (35 points) The slab is to be hoisted using the three slings shown. (The force F1 is vertical.) a. Replace the system of forces by an equivalent force and couple moment at point 0. b. Replace the system of forces by one equivalent resultant force, and specify its location (x,y) on the slab. ii: Flszf‘Fz ,3 : éww F3=4kN + ['9ch 5‘04’g9nnDJ0 L +6 I”cpl‘fscz‘oﬁgob 3 +5 JMASOZJ . 54’“ “L [Ark/NQIHOO" L +COIQOJ “C034 ")3 x ’ .5 )LM d A .s , . I: _ (owl: + (4370’ng t aocl‘ly 3555'” +(waZJﬂﬁZb4lL) 4’)w ..\ ‘0 __‘ —> : LO Z§ZZL+§ 00(qJ—f‘Q’QJG .a '4 .3 Bung oﬂ ()ch 9*) PK _. _\ L J k, / of! PIA/Mk 3) r j f y 4*“ o 0 lo 9930 q ‘ '7“: ' 1m GM 0 3,5359W MED Zé 0 o g" «1375,78 "Bum” MW elbciaizj] +[ ”405355) wizowqﬁlg . —> , ma F2 0,232.74» OQZJQ w .» MR0 {3m £44423 + (2.21.372) C H23” l!“ ‘L A —> ._I - ‘J. .._‘+ (223*, b) (mpg E2) 2(er)-1\M2o Mao éGL 2W“; ‘ ‘4 A a ‘ b )V“ L 9 4 1.12246?) —I . 4, Km Um O : (audit! 23+ . 3 c62,3o43),juzac QHXSTHZXSLLE) —o N 1371*" 50M“ izxwr" _ (tact—u. '42} J. (2,1452) M BONUS (+ 3 points): Answer one of the following bonus problems. =5 l2 3b43'v3" '2 0' '37 (23L4x:"2{p,|4 -21"M 1. Students who take the SAT are automatically awarded 400 points for spelling their name correctly. True 0 . false? 1% U6 2. Determine the angle Bat which the 500-N force must act at A so that the moment of this force about point B is equal to zero. ' , ~§oo3m (9(3'“) + SOOCMGLOFD " D ' 5 V’ 05670 (DOOS‘AG * (SOC Page3 of3 ...
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