Sol_set__2 - PD F-XChange PD F-XChange W N O y bu to k C...

Info icon This preview shows pages 1–5. Sign up to view the full content.

View Full Document Right Arrow Icon
1. Consider an abrupt P+N junction with N a =2x10 18 cm -3 and N D =1x10 15 cm -3 . If the minority carrier lifetime is W p =1x10 -6 sec. a) Calculate and graph the p n (x) for a long diode of length L=100um (boundary condition p n (L)=p n0 ) . b) Calculate the current for a forward bias of .5V. c) Repeat a&b for a short diode of length 2.3 microns (boundary condition p n (L)=0). Click to buy NOW! P D F - X C h a n g e w w w . d o c u - t r a c k . c o m Click to buy NOW! P D F - X C h a n g e w w w . d o c u - t r a c k . c o m
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Click to buy NOW! P D F - X C h a n g e w w w . d o c u - t r a c k . c o m Click to buy NOW! P D F - X C h a n g e w w w . d o c u - t r a c k . c o m
Image of page 2
Click to buy NOW! P D F - X C h a n g e w w w . d o c u - t r a c k . c o m Click to buy NOW! P D F - X C h a n g e w w w . d o c u - t r a c k . c o m
Image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
X=1:.01:100 %microns LP=5 Dp=4 tau=1e-6 L=100 LP=sqrt(Dp*tau)/1e-4 V=.5 Pno=1.45e10^2/1e15 Pn=Pno*exp(V/.0259) %P=Pn*(cosh(X/LP)-coth(L/LP)*sinh(X/LP))+Pno P=Pn*(sinh((L-X)/LP)/(sinh(L/LP))) plot(X,P) xlabel('Microns') ylabel('Carrier Concentration') I=Pn*(1.602e-19*Dp/LP)*(cosh((L)/LP)/(sinh(L/LP))) end Click to buy NOW!
Image of page 4
Image of page 5
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern