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# - 1 F = mg 2 N W = 0(equilibrium 3 T Warm F = 0(for reverse curls 4 2F W upper body = 0(for close grip lat pull down Pulley Question 9 and 10 9

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1) F = mg 2) N – W = 0 (equilibrium) 3) T – W arm – F = 0 (for reverse curls) 4) 2F – W upper body = 0 (for close grip lat pull down) 5) a = v /t 6) F = ma Pushing Objects questions (7 and 8) 7) a = f / m 2 F- f = m 1 / m 2 * f 8) f = F net x [m 2 / (m 1 + m 2 )] (action – reaction force, force between objects) Pulley Question ( 9 and 10) 9) Object M: T = Ma Object m: T – mg = ma mg = Ma + ma 10) a = g x [ m / (m+M)] 11) F ext = (m 1 + m 2 + m 3 ) a 12) T 2 – T 1 = m 2 a 10 The figure shows an object on an inclined  plane. Two forces act on the object: the normal force N, and the weight W. As a result of these  forces, the object accelerates downhill. Which equation is the correct equation of motion  in the shown x-direction? Hint: remember that "W" and "a" represent the  magnitude of a vector. A + WsinF = - ma               D + WcosF = - ma B - WsinF = - ma                 E - WcosF = - ma C - WcosF = + ma

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An object has a volume of 5 cm3.
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## This note was uploaded on 04/04/2009 for the course PHYS 2028 taught by Professor Campbell-brown during the Spring '09 term at UWO.

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- 1 F = mg 2 N W = 0(equilibrium 3 T Warm F = 0(for reverse curls 4 2F W upper body = 0(for close grip lat pull down Pulley Question 9 and 10 9

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