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Unformatted text preview: revolving the curve y = 1x 2 , x 1 about the yaxis. Solution: We use A = Z 2 x p 1 + ( y ) 2 dx. We have y =2 x, so A = Z 1 2 x p 1 + 4 x 2 dx. Take u = 1 + 4 x 2 , then du = 8 x dx, so Z 2 x p 1 + 4 x 2 dx = 4 Z u 1 2 du = 4 2 3 u 3 2 + C = 4 2 3 (1 + 4 x 2 ) 3 2 + C. So A = h 6 (1 + 4 x 2 ) 3 2 i 1 = 6 (5 3 21) ....
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This note was uploaded on 02/29/2008 for the course MATH 22 taught by Professor Dodson during the Summer '05 term at Lehigh University .
 Summer '05
 Dodson
 Arc Length, Improper Integrals, Integrals

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