Phys 0175 - Lecture 18

Phys 0175 - Lecture 18 - Lecture 18 (Feb. 23, 2009):...

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Lecture 18 (Feb. 23, 2009): Chapter 27: Circuits (cont’d) Analyzing a circuit with resistors in combination Illustrative Examples Analyzing multiloop circuits using Kirchhoff’s Rules (conservation of charge and energy) Illustrative examples
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Resistors in series have the same current passing though all resistors; therefore V = V 1 + V 2 + V 3 + … = I*R 1 + I*R 2 + I*R 3 + …= I*(R 1 + R 2 + R 3 + …) = I*R eq R eq = R 1 + R 2 + R 3 + … Resistors in parallel have the same voltage across them; therefore I = I 1 + I 2 + I 3 + … = V/R 1 + V/R 2 + V/R 3 + …= V*(1/R 1 + 1/R 2 + 1/R 3 + …) = V/R eq (1/R eq ) = (1/R 1 + 1/R 2 + 1/R 3 + …)
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Illustrative Example 18.1: Steps in reducing a combination of resistors to a single equivalent resistor and finding the current in each: 1/(6Ω) + 1/(3Ω) = 1/(2Ω) 4Ω + 2Ω = 6Ω 18V/6Ω = 3A 3A*4Ω = 12V 3A*2Ω = 6V 6V/6Ω = 1A 6V/3Ω = 2A
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Illustrative example 18.2: Two identical light bulbs in series and in parallel: R eq = 4Ω I = 2A R eq = 1Ω I total = 8A I 1 = I 2 = 4A I 1 I 2 I total = I 1 +I 2
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Illustrative Example 18.3: The diagram shows a
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Phys 0175 - Lecture 18 - Lecture 18 (Feb. 23, 2009):...

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