# example 10-2 - Example 10-2 Oil flows through a gradual...

This preview shows pages 1–2. Sign up to view the full content.

Example 10-2 Oil flows through a gradual contraction in a pipe, as shown. A manometer containing mercury and oil is used to determine the pressures in the upstream and downstream locations. Assuming inviscid flow, and using data on the figure, calculate the mass flow rate. Solution: Use the manometer to determine the pressure drop along the center streamline. The pressure at the bottom of the left leg of the manometer equals the pressure at the bottom of the right leg, therefore () ( ) 13 1 1 23 2 oH g o 2 H g Pg hh g hP g gh ρ ρρ +− += + 12 1 1 2 2 go H g P h g hg h −= + ( ) 21 g P h h g h h − + ( ) H go PP g h h

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
3 kg rho_('Mercury-liquid',20) 13546 m Hg ρ == () 33 kg kg 0.77 1000 770 mm ow a t e r SG ρρ = The pressure difference along the center streamline is 12 23 m4 . 41 . 7 k g 9.81 m 13546 770 s1 0 0 PP m ⎛⎞ −= ⎜⎟
This is the end of the preview. Sign up to access the rest of the document.

## This note was uploaded on 04/06/2009 for the course ENGR 2250 taught by Professor Borca-tasciuc during the Spring '08 term at Rensselaer Polytechnic Institute.

### Page1 / 2

example 10-2 - Example 10-2 Oil flows through a gradual...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online