# example 13-2 - Example 13-2 Steam at 300C and 200 kPa is...

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Example 13-2 Steam at 300°C and 200 kPa is contained in a rigid tank of volume 0.36 m 3 . The tank is cooled while 350 kJ of heat are removed. a) Find the final pressure b) Show the process on a P-v diagram Solution: From the first law UQW ∆=− Volume is constant and no work is done, therefore UQ ∆= () 21 mu u Q −= 1 kJ intenergy(steam, 300, 200) 2808 kg uT P == = = Use specific volume to find the mass 3 1 m volume(steam, 300, 200) 1.32 kg vT P = = 3 3 1 0.36m 0.274kg m 1.32 kg V m v = To fix the final state, we need two properties. We can use

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example 13-2 - Example 13-2 Steam at 300C and 200 kPa is...

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