This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: Name: ___________— RIN:
{Kc .7 Problem #1 (40 points, 8 points each part)
1' ‘ I i A player hits a 202 tennis ball with a horizontal initial velocity of v1 = 54 ft/s at a height of y1 = 4.5 ft.
The ball bounces at point A and rises to a maximum height of y4 = 3 ft where the velocity is v, = 30
ft/s. Knowing that the duration of the impact is Atzg = 0.004 5, determine the impulsive force vector
F23 exerted on the ball at point A. The subscripts 2 and 3 indicate the times just before and after the
impact at A. a) Find the vector velocity of the ball just before impact vz. b) Find the vector velocity of the ball just after impact V3. c) Write an equation for the impulse Imp on the ball during the impact 23 in terms of v; and V3. (1) Find the vertical impulsive force (F023 exerted by the ground on the ball. e) Find the vertical impulsive force (F1023 exerted by the ground on the ball. ”) léx’l/xx=54 74/5 1/23 [€307 meﬂopéZ/ZQﬂk “7/7904 Ada z/zr ; %:ﬂ,ﬂ03&0 Jﬂ/j ﬂ ;4€574 (7: 3%; 74/5 2 «J'ﬂff‘éﬂow/y
A /
4 “V2 =547"/7~,0j
5) mm“ gxm=gwe nyﬁ/E’ﬂz”
A1940 7‘ +37% 744/5 V
' 7/” L A; 7 mp3
5/ 427‘ f3 A! ~
,3 A
{jp‘fﬁ 41/23 fzs‘ﬁfw‘ Fj/jNﬁ/j
«Z ' 4 V,“ M”
6) a: {Edi/Tag "W W MK,ng Ms
A’QB A7523
«23.3 /A Name: _________________________ RIN: Problem #2 (30 points, 6 points each part) A system consists of three identical 9kg particles A, B and C. The velocities of the particles are, respectively, VA = vA j, V3 = v3 i, and vc = vc k, and the magnitude of the linear
momentum L of the system is 45 kgm/sf For this special case HG: H0, which means that m X L = 0; which, in turn, means that re and L are in the same direction. The symbol HG denotes the angular momentum vector of the system about its mass center G, and H0 is the angular momentum of the system about 0. a) Find the position vector of the mass center m. b) Find the vector L. c) Find the velocities VA, V3, and vc. '
7 d) Find Ha. f6 :ﬂ. 37% /. 2 j‘
e) How many‘points for this part? kﬂrﬂébKW) ~Q:ﬂ,é7‘+ﬂéj‘+ﬂgz A ﬂ é/uﬂgz
4] (Mfr/(A‘LMBIE +m‘[‘>7ﬂgl + ’ j '
~6 M+MB+ML A
,r 4"&“g 5/] =_£é—;ﬂ3337‘ +3567j4 4’0567'4’
ﬁb/z/gf—gfgﬁ Hf +30% + go 3,, H
' ’\ Icy/M
__ /\ /\ A /
5/ paw/waywarﬂvm WW7” 5
~ M _ ﬂ 1
%:333 569» ng/M7—g‘ [4/3335 M”. ii;
I V *[él’ymol/L
H s FAX/WMW'SE’WLB A
4/) “6 N " r’ayzf‘eﬂdé
4vé4+ﬂu3h ~23" A
r” “Wéhﬂ’g/ ﬂ 7 I, M MA
#2 ’ A” c a a —
A 4 " M77
, , 4 (’Qoﬂjx majw Nag/um. L
#9 ' 7'/d'§/ & j A ( [ /\ Merv: Name: RIN; Problem #3 (30 points)
The assembly shown consists of two rods and a rectangular plate BCDE which are welded together. The assembly rotates about the axis AB with an angular velocity of 10 rad/s that decreases at the rate of
20 rad/s2 The rotation is counter clockwise as viewed from B. Determine the velocity and acceleration of corner C. é‘ : [M4 :ﬂ.S’/A«ﬂ/36féﬂ.yf; r 3arﬂ+ﬂ§4 M
B/ﬂ » xv F 4
J79; ﬂjjjj 4
/l . /l fﬂf/ «M2251? ¥d,
[5/4 W
)FB/ﬂl: ﬂﬁltf’ﬂ'zggﬁ'mjj'
a 525’
/\
:. ,gé
[O ﬂ
« f
l' /\
/ m :45 3300 mm x , , r ,
ﬂc’QC/B’M XAC/E N 4
4 Mgr/43 éf+¢82]x {—2.z/f—/Iaé)_J : Aim/Wit“ A 1”" MM +/$47j1—Wdﬂ ...
View
Full Document
 Spring '09
 JohnTichy
 Dynamics, Angular Momentum, Force, Mass, Momentum, vertical impulsive force

Click to edit the document details