hw 30001 - SOLUTION W1 W2 W3 000 001 -010 011 -100 101 -110...

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SOLUTION W1 W2 W3 f MUX W1 W3 W2 f MUX W2 W3 W1 f MUX 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 W3 0 0 1 1 W2 0 0 1 0 ------------------ --------- --------------- ----------------- --------- --------------- ----------------- --------- ---------------- 0 1 0 1 1 0 1 0 1 1 0 1 0 1 1 0 1 1 1 0 1 1 1 0 1 1 1 ------------------ --------- --------------- ----------------- --------- --------------- ----------------- --------- ---------------- 1 0 0 0 1 0 0 0 1 0 0 1 1 1 0 1 1 W3 1 0 1 1 W2 1 0 1 1 ------------------ --------. --------------- ----------------- --------- --------------- ----------------- --------- ---------------- 1 1 0 1 w 3 1 1 0 1 - 1 1 0 1 - 1 1 1 0 1 1 1 0 w 2 1 1 1 0 w 1
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W1 W2 W3 f MUX W2 W1 W3 f MUX W3 W1 W2 f MUX 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 W2 + W3 0 0 1 1 0 0 1 1 0 1 0 1 0 1 0 0 W3 0 1 0 0 W2 0 1 1 1 0 1 1 1 0 1 1 1 ------.----------~ -.-._-._- --------------. -------------.--- ----.---- --.--.-.--.-.-- --.----.--.-.--.- ---.-._-. -.-.--.-.--.-.-- 1 0 0 0 1 0 0 1 1 0 0 1 1 0 1 1 w 2 EBw 3 1 0 1 1 -- 1 0 1 1 -- 1 1 0 1 1 1 0 1 W 1 W 3 1 1 0 1 W 1 W 2 1 1 1 0 1 1 1 0 1 1 1 0 2. (2 Points) The easiest solution is to derive a truth-table for the circuit; then derive an algebraic expression from the truth-table. w
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hw 30001 - SOLUTION W1 W2 W3 000 001 -010 011 -100 101 -110...

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