hw2-solns

# hw2-solns - Illinois Institute of Technology Department of...

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Unformatted text preview: Illinois Institute of Technology Department of Computer Science Solutions to Homework Assignment 2 CS 430 Introduction to Algorithms Spring Semester, 2009 Due: Wednesday, February 11 1. Problem 6.4-3 on page 136 The problem is to get the running time of heapsort on an array A of length n that is already sorted in increasing order or decreasing order. We need to define the heapsort and refer HEAPSORT( A ) on page 136 to get its running time. Heapsort is to sort elements in the input array in increasing order or decreasing order in place. The im- plementation will probably be different per each person, but we will consider the running time through HEAPSORT( A ) on page 136. As the book mentions on page 136, HEAPSORT( A ) consists of two different procedures: BULID-MAX- HEAP and MAX-HEAPIFY. To get the running time, we need to figure out the running time of both BULID-MAX-HEAP and MAX-HEAPIFY. In the former, BULID-MAX-HEAP is to construct max-heap from the original input array, termed as A , and we can get the modified array, termed A . We can easily figure out the BULID-MAX-HEAP procedure makes the same A regardless of the original array A . In the latter, MAX-HEAPIFY is to reorder the array A to sort in increasing order. For both cases, MAX-HEAPIFY takes the same time, O ( nlgn ). In the case A is sorted in increasing order, ∑ b lgn c h =0 d n/ 2 h +1 e O ( h ) = O ( n ∑ b lgn c h =0 h/ 2 h ). ∑ b lgn c h =0 h/ 2 h = 1 / 2 + 2 / 2 2 + 3 / 2 3 + 4 / 2 4 + ... ≤ 1 / 2 + 2 / 2 2 + 2 / 2 2 + 4 / 2 3 + 4 / 2 4 + 8 / 2 5 + 8 / 2 6 + 8 / 2 7 + ... = 1 / 2 + 1 / 2 2 + (1 / 2 + 1 / 2 2 + 1 / 2 3 + 1 / 2 4 + ... ) = 1 / 2 + 1 / 4 + 1 = 1 . 75 (As n → ∞ ) In Big-Oh notation, we can ignore any coefficient which is constant, and O ( n ∑ b lgn c h =0 h/ 2 h ) = O ( n ). In the case A is sorted in decreasing order, we do not need to move since Parent( i ) ≥ Left( i ) and Parent( i ) ≥ Right( i ). However, we have to check all nodes in the input array A , we need to visit each node exactly once. Then, we do not care about the hight of each node, we only need to consider how many nodes are in the array, O ( n ). In conclusion, in either case, the running time depends on MAX-HEAPIFY, O ( nlgn ). CS 430—Spring, 2009 2 Solutions to Homework Assignment 2 2. Problem 7.4-5 on page 159 This problem is composed of two parts: argue that this sorting algorithm runs in...
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## This note was uploaded on 04/07/2009 for the course CS 430 taught by Professor Kapoor during the Spring '08 term at Illinois Tech.

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hw2-solns - Illinois Institute of Technology Department of...

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