Ligan Binding Calculations

Ligan Binding Calculations - Step 2. A=cl With an...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
. Step 2 =ℰ A cl , With an extinction coefficient of 33 900 M - 1 ·cm - 1 , , and a path length of 1cm we . should get an absorbance of 0 2 if the chromophore is in a concentration given by = / c A ℰ = l . / * = . 0 2 33900 1 5 9 x 10 - 6 M so we are looking for our bound HABA concentrations to be in a range around . 6μM . Step 4 . We want the absorbance of about 0 2 to be near the point where half the , HABA is bound to avidin so since the binding of avidin with its ligands is very , . tight the avidin should be about twice the concentration of HABA We saw in . step 2 that this is about 6μM So we want all the tubes to have about 12 μM . ; / . avidin Avidin is expensive we only have about 1mL of 25mg mL of material , The MW of the avidin tetramer is 68 kD and there must be at least 4 . / receptors per tetramer So since the 25mg mL stock solution is the same as 25 / ( ), ( / )/( g L just changing the units we can write 25g L 68x10 3 / ) = . g 4 mol 1 47mM is . the minimum concentration of receptor in the avidin stock solution
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 04/07/2009 for the course CHE 331L taught by Professor Brunet during the Spring '09 term at American International.

Page1 / 3

Ligan Binding Calculations - Step 2. A=cl With an...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online