solution hw assignment 40001

solution hw assignment 40001 - 3 ..... . )(.. .. X-1-x-3 )....

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2.30. (2 Points) f(X 1 ,X 2 ,X 3 ,X 4 )= L(7,11,13,14,15) =~~~~+~~~~+~~~~+~~~~+~~~~ = (x 1 x 2 x 3 x 4 + x 1 x 2 x 3 x 4 )+ (x 1 x 2 x 3 x 4 + x 1 x 2 x 3 x 4 )+ (x 1 x 2 x 3 x 4 + x 1 x 2 x 3 x 4 )+ (x 1 x 2 x 3 x 4 + x 1 x 2 x 3 x 4 ) =x 2 x 3 x 4 + x 1 x 3 x 4 + x 1 x 2 x 4 + x 1 x 2 x 3 2.36. (6 Points) a. truth-table X1 Xo o 0 o 0 o 0 o 0 o 1 o 1 o 1 o 1 1 0 1 0 1 0 1 0 1 1 1 1 1 1 1 1 1 0 o 0 o 1 1 0 1 1 o 0 o 1 1 0 1 1 o 0 o 1 1 0 1 1 o 0 o 1 1 0 1 1 b. Canonical SOP: f = x 1 X o Y1 Yo + x 1 X o Y1 Yo + x 1 X o Y1 Yo + x 1 X o Y1 Yo + x 1 X o Y1 Yo + x 1 X o Y1 Yo + - - - - ~~~~+~~~~+~~~~+~~~~ 2.41. (3 Points) There are two minimal SOP expressions for the function is { X1 x 3 + x 1 x 3 + x 1 x 2 = «x 1 x 3 )(X 1 x 3 )(x 1 x 2 )) f = X 1 X 3 + x 1 X 3 + X 2 X 3 = -«X- 1 -X-
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Unformatted text preview: 3 ..... . )(.. .. X-1-x-3 ). ... (X-2-X-3-- 2.43. (3 Points) The minimal POS expression for the function is f = (x 1 + x 3 )(x 1 + x 2 + x 3 ) = 7tX=1=+=X=3"')-+T-(X=1=+=X=2=+=X=3"'))...
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solution hw assignment 40001 - 3 ..... . )(.. .. X-1-x-3 )....

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