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Review

# Review - Review Chapter 21 Electromagnetic radiation...

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Review

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Chapter 21 Electromagnetic radiation c=3.0x10 8 m/s E/B=c c=fλ 2 2 max max 2 2 o o B c E Power area c μ μ = = RLC circuits and resonance max 2 rms v v = max 2 rms I I = V IZ = ( 29 2 2 L C Z X X R = - + 1 2 c X fC π = 2 L X fL π = transformer 1 1 2 2 V N V N = 1 1 2 2 I V I V =
18. An RLC circuit with R= 500 Ω C= 4.4x10 -6 F and L =0.4 H is in series with a 50 Hz generator and produces a rms current of 0.25 A. a) Find the required maximum voltage ΔV. b) Find the phase shift between I and ΔV. R L C 2 2 2 2 6 2 2 1 (2 ) 2 1 (2 (50)(0.4) ) 500 2 (50)(4.4 10 ) (126 723) 500 780 Z fL R fC Z x Z π π π π - = - + = - + = - + = max max 2 rms V I Z I Z = = max 0.25(1.41)(780) 222 V V = = a)

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18. An RLC circuit with R= 500 Ω C= 4.4x10 -6 F and L =0.4 H is in series with a 50 Hz generator and produces a rms current of 0.25 A. a) Find the required maximum voltage ΔV. b) Find the phase shift between I and ΔV. R L C 126 723 tan 1.19 500 50 L C o X X R - - Φ = = = - Φ = - b) X L X C R Z Ф
40. A transformer has N 1 = 350 turns and N 2 =2000 turns. If the input voltage is ΔV =170cos(ωt) what rms voltage is developed across the secondary? 1 1 2 2 V N V N = 1max 2 2 2 1 1 1 2 2 (170)(2000) 687 2(350) rms rms rms V N N V V N N V V = ∆ = = =

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Chapter 20 magnetic flux cos B BA θ Φ = θ Faraday’s law B N t ε ∆Φ = - Lenz’s law direction of current opposes ΔΦ motional emf ε=B v rotating coil sin NAB t ε ϖ ϖ = B I L t ε = - Inductors B N L I Φ = 2 o N A L μ = l (for solenoid) PE=½LI 2 L R τ =
6. A current of 10 A is flowing through a inductor L and resistor R and through a switch. If the switch is quickly opened, the voltage across the inductor __________. a. decays with a time constant RL b. decays with a time constant L/R c. increases rapidly d. decreases rapidly to zero.

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Review - Review Chapter 21 Electromagnetic radiation...

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