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Unformatted text preview: Platt, David Homework 4 Due: Sep 14 2005, 4:00 am Inst: Ken Shih 1 This printout should have 12 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. The due time is Central time. Again! For 005, you need to answer in unit of uC (miu Coulomb,*E6C). 001 (part 1 of 3) 10 points An electric field of magnitude 3450 N / C is applied along the x axis. Calculate the electric flux through a rect angular plane 0 . 214 m wide and 0 . 41 m long if the plane is parallel to the yz plane. Correct answer: 302 . 703 N m 2 / C. Explanation: Let : E = 3450 N / C , = 0 , L = 0 . 41 m , and W = 0 . 214 m . The area of the rectangle is A = LW = (0 . 41 m)(0 . 214 m) = 0 . 08774 m 2 . Since the field is uniform,the flux is = E A = E A cos = (3450 N / C)(0 . 08774 m 2 )(cos0 ) = 302 . 703 N m 2 / C . 002 (part 2 of 3) 10 points Calculate the electric flux through the same rectangle, if it is parallel to the xy plane. Correct answer: 0 N m 2 / C. Explanation: The angle is = 90 ,cos = 0 , and = E A = E A cos = (3450 N / C)(0 . 08774 m 2 )(0) = 0 N m 2 / C . 003 (part 3 of 3) 10 points Calculate the electric flux through the same rectangle, but now the rectangle contains the y axis and its normal makes an angle of 26 with the x axis. Correct answer: 272 . 068 N m 2 / C. Explanation: Let = 26 = E A = E A cos = (3450 N / C)(0 . 08774 m 2 )(cos26 ) = 272 . 068 N m 2 / C . 004 (part 1 of 1) 10 points A (9 . 31 m by 9 . 31 m) square base pyramid with height of 3 . 32 m is placed in a vertical electric field of 59 . 9 N / C. 9 . 31 m 3 . 32 m 59 . 9 N / C Calculate the total electric flux which goes out through the pyramids four slanted sur faces. Correct answer: 5191 . 9 Nm 2 / C....
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This note was uploaded on 04/10/2009 for the course PHY 303L taught by Professor Turner during the Fall '08 term at University of Texas at Austin.
 Fall '08
 Turner
 Physics, Work

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