HW9Sol - Platt, David Homework 9 Due: Sep 28 2005, 4:00 am...

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Unformatted text preview: Platt, David Homework 9 Due: Sep 28 2005, 4:00 am Inst: Ken Shih 1 This print-out should have 9 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. The due time is Central time. For 004, just give the ratio of the stretched value to its original value. 001 (part 1 of 3) 10 points A 70 resistor is connected to a 9 . 5 V battery in the circuit below. 70 9 . 5 V S I a) When the switch is closed, calculate the current I . Correct answer: 0 . 135714 A. Explanation: Let : V = 9 . 5 V and R 1 = 70 . R = V I I 1 = V R 1 = 9 . 5 V 70 = . 135714 A . 002 (part 2 of 3) 10 points A 56 resistor is connected to a 9 . 5 V battery in the circuit below. 56 9 . 5 V S I b) When the switch is closed, calculate the current I . Correct answer: 0 . 169643 A. Explanation: Let : R 2 = 56 . I 2 = V R 2 = 9 . 5 V 56 = . 169643 A . 003 (part 3 of 3) 10 points A 18 resistor is connected to a 9 . 5 V battery in the circuit below. 18 9 . 5 V S I c) When the switch is closed, calculate the current I . Correct answer: 0 . 527778 A. Explanation: Let : R 3 = 18 . I 3 = V R 3 = 9 . 5 V 18 = . 527778 A . 004 (part 1 of 1) 10 points A wire with a circular cross section and a resistance R is lengthened to 9 . 44 times its original length by pulling it through a small hole. After being pulled through the hole, the total volume of the wire is unchanged....
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This note was uploaded on 04/10/2009 for the course PHY 303L taught by Professor Turner during the Fall '08 term at University of Texas at Austin.

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HW9Sol - Platt, David Homework 9 Due: Sep 28 2005, 4:00 am...

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