FL answers - 10-6 m 3 /s 3.28 1.40 mph FL12 (a) 1.098 kg/s...

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Fluid Mechanics Homework Answers – ME 2124 – Spring 2009 Problem Answer(s) FL1 (a) 265 kPa (b) 196.2 Pa FL2 (a) 0.6079 kg/m 3 (b) 1.2756 kg/m 3 (c) -98.3 Pa FL3 higher, equal, can’t determine, higher FL4 1000 N/m 2 FL5 (a) diagram (b) F = mg sin θ (c) sketch (d) F = A μ v/h (e) v = mgh sin / A (f) lower 1.61 i o i R R l R = μω π τ 3 2 2.26 -802 psf FL6 B and C FL7 (a) 250 ft/s (b) 3.39 lbm/s FL8 141.2 ft 3.17 Fig. (a) 3.24 -76.0 lbf/ft 2 gage, +88.0 lbf/ft 2 gage FL9 11.46 m, 112 kPa, momentum change FL10 (a) v= (2 gh ) 1/2 (b) 2.21 m/s (c) 43.4 ml/s (d) Decreases FL11 (a) 18 m/s (b) 52.9 m/s (c) -1399 Pa gage (d) Yes 3.26 2.45 × 10 5 kPa, 5.50
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Unformatted text preview: 10-6 m 3 /s 3.28 1.40 mph FL12 (a) 1.098 kg/s (b) No FL13 13.9 ft/s 3.25 0.152 ft 3 /s, -125 lbf/ft 2 3.30 1.56 D 2 m/s FL14 Water FL15 1,610,000 FL16 18.38 ft 7.33 109 mm 7.37 3760 mph, not realistic FL17 0.1092 m/s FL18 (a) D V & 4 Re = (b) 15,530 (c) Turbulent FL19 (a) 43.0 psi (b) -13 psi (c) 0.312 psf FL20 (a) Laminar (b) 30.6 kPa gage FL21 (a) R v Max v 2 = (b) 1.08 Pa (c) 1200 Pa (d) 4.24 Pa (e) = 0 FL22 1.095 D FL23 (a) Turbulent (b) 24.5 psi FL24 24.8 psi FL25 25.4 psi FL26 (a) 2.234 m/s, 1,113,000 (b) 77.7 kPa/km, 77.700 kPa (c) 682 kW 8.71 0.325 psi...
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This note was uploaded on 04/10/2009 for the course ME 2124 taught by Professor Uzgoren during the Spring '08 term at Virginia Tech.

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FL answers - 10-6 m 3 /s 3.28 1.40 mph FL12 (a) 1.098 kg/s...

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