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Unformatted text preview: % Homework 1b Part Two clear d = 9.98; % Density of orange c = 3900; % Specific heat of orange h = 6; % Convective heat transfer coefficient %~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ % initial temperature at 20 degrees % arbitrary time since t is unknown %~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ % radius is 2.5 cm for r = 2.5; v = (4/3)*pi*(r^3); % Volume of orange a = 4*pi*(r^2); % Area of orange m = d*v; % Mass of orange t = 1:9000 % time in seconds Ti = 20; % Harvest Temperature of 20 degrees Tf = 3; % Cold Storage Temperature T(t) = Tf + (TiTf)*exp(((h*a)/(m*c))*t); end subplot(6,1,1), plot (t,T) % radius is 3.0 cm for r = 3; v = (4/3)*pi*(r^3); % Volume of orange a = 4*pi*(r^2); % Area of orange m = d*v; % Mass of orange t = 1:9000 % time Ti = 20; % Harvest Temperature of 20 degrees Tf = 3; % Cold Storage Temperature T(t) = Tf + (TiTf)*exp(((h*a)/(m*c))*t); end subplot(6,1,2), plot (t,T) % radius is 3.5 cm for r = 3.5; v = (4/3)*pi*(r^3); % Volume of orange a = 4*pi*(r^2); % Area of orange...
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This note was uploaded on 04/11/2009 for the course ENG 100 taught by Professor Delwiche during the Spring '08 term at UC Davis.
 Spring '08
 Delwiche
 Heat Transfer

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