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(210.1 g)(0.3702 m/s) = 77.8 g m/s
M
a
V
a
= 0 + (209.3 g)(0.3778 m/s) = 79 g m/s
Atinuke Omolara
Physics Lab 1061
Momentum Elastic and Inelastic Collisions
March 16, 2009
Objective:
To study momentum and the conservation of energy in one dimensional collisions
Introduction:
Collisions between two (or more) objects provide a good case to study both the conservation of
momentum and conservation of kinetic energy. The former is the conservation of a vector and
the latter a scalar quantity.
The change of the momentum of an object is given by the time integral of the force acting on the
object. From Newton’s third law, i.e. action–reaction principle, the forces exerted by two objects
on each other during a collision are equal and opposite. Therefore the changes of momentum of
the two objects are equal and opposite. Then if there are no external forces acting on the objects,
the total momentum of the two objects remain the same.
The conservation of the kinetic energy requires that the force exerted by the two objects on each
other during the collision must be conservative. In mathematical terms this means that the force
is related to a potential energy. Before the collision, let’s take the potential energy to be zero.
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 Spring '09
 tsankov
 Physics, Conservation Of Energy, Energy, Momentum

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