question7 - k++) { if (*(str+k) == chr) { return(str +k) }...

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Sheet1 Page 1 const char* findChar(const char str[ ], char chr) { for (int k = 0 *(str+k) !=0
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Unformatted text preview: k++) { if (*(str+k) == chr) { return(str +k) } } return NULL }...
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This note was uploaded on 04/12/2009 for the course CS 31 taught by Professor Melkanoff during the Winter '00 term at UCLA.

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