Soltn11 - Homework 10-1,1(a Er = 7.05 at 0 K for copper eV t =;t =(7.05eV)=423eV(b = E(permolecule!k = n.u"u T= 1 11 Solutions(423evf1.5x lo{e

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Homework 11 Solutions 10-1,1 (a) Er = 7.05 eV at 0 K for copper. 1? t " =;t, =:(7.05 eV)=423 eV (b) E."(per molecule) = !k", = n.u "u (423 evf1.5 x lo{e t/ev) T= , =. -' ' =3.77xl0'K=327O0K (1.s)(l.38 x 10-- ,/K) IVZT p=0.%1 Elcmt M=23.0 g/mole (sodium) (a) n =N sP M n = (6.ux10ts el€ctrons/molex0.9l g/cn![ze.o g/mote) n = 2.54xl}n electrons/crr3 = 2.54 x 108 electrons/m3 104 electons/m3 8n (b) Et = Er= (c) Dr = vE- ]" to-Lt d=t mm=10-r m; v=(ro-3 m)3 =10a m3 The densitv of states = ral = cEaz = [W2 4:IEvz th'l gg = eqzyvz fe tx 1o-3r kg)ry2 s(E) = (8.50 x 105)rrr-3 ;{ =(t36x1oz)n-3 ev-r 1 /m(E)=p;;rfu6 or /tot*oev)=7;;;*;1",*u-*, - =4 -=' So the total number of electronr = N = gQ)\M)Vlpg) ot ru=(t-arxroz m-3 evi |0.025 ev{toa m3Xt) g.lo x t017. ft+o ev{r.oxto'e I^vIv2 (s.ozsxtoa ys)' h2 1ln14t hrrlsr) | 1o.os " ro-" y';' l;a " z.sl " titrr-lFElll"- 5.O4x 10-re | 3.15 ( zEF\v2 zxs.Mt lo-t, IIV' i;/ =l;n'ro;rru-j 1.05x105 try's
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\,J-ab) fi rr is tdc huvnbar- ol un/.vdim d<rJu-s ?er c\^3 a,^0' t(c <,led,urns n\vw 4t vdou\ q ft^ +6"-;; ir. ,( e\aJ*,o nJ a(;i h* -"4- tfur^ {fu. y\rJynber u( elLd*o #'d aF; t 4,rJ poin-l in f;nnc &L is \-/ Lrv= ^"AqAt u"A-n * is tft- Crrss tu-Jow^l 0^!a hL$ dv^rgr- €- ,So l(tv- t'v* &ux"xu s " AO= 1..-Ln^ e Nffd!+ 50 o€ ttL wire.
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This note was uploaded on 04/12/2009 for the course PHYSICS 7C taught by Professor Lin during the Fall '08 term at University of California, Berkeley.

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Soltn11 - Homework 10-1,1(a Er = 7.05 at 0 K for copper eV t =;t =(7.05eV)=423eV(b = E(permolecule!k = n.u"u T= 1 11 Solutions(423evf1.5x lo{e

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