20081ee110_1_hw5_sol-1

# 20081ee110_1_hw5_sol-1 - Solution 1(a(b Solution 2(a To...

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Unformatted text preview: Solution 1. (a) (b) Solution 2. (a) To complete the sketch, we need to first find ω , which we obtain in part (b). (b) 1 2 2000 rad/s or 318.3 Hz f ω ωω = = = (c) B = 2 1 3000 rad/s or 477.5 Hz ω ω − = (d) 2 1 2000 0.667 3000 Q ω ω ω = = = − 4 4 5 4 8 3 8 2 4 4 8 8 2 4 Apply 1V. I 10 A 1 Y I 10 (1 [10 ( 10 )])10 4.4 10 1000 48.4 10 4.4 10 1000 Y 10 11 10 4.4 4.4 1000 48.4 10 4.4 10 Y ( ) 4.4 − − − − − − − − − − − ± ∴ = − ∴ = = + + − − × × + × + ∴ = + + × = − × + × ∴ = R in in in in s s s s s s s j j j ω ω ω ω 8 2 1 4 At , 1000 48.4 10 , 45.45 krad/s 4.4 10 Z ( ) 10 4.4 − − − − = = × = × = = Ω o o o o in o o j j k j ω ω ω ω ω ω ω Solution 3. (a) (b) 3 0.1 K 250, K 400 0.1F 1 F 250 400 2 250 5 1250 , 2H 1.25H, 4I 10 I 400 = = ∴ → = μ × × Ω → Ω → = → m f x x 3 6 1250 3 3 6 3 6 3 3 3 3 1 10 . Apply 1 V I 10 , I 1250 1 10 1000 I 10 I 1.25 1 0.8 0.8 I 10 (1 10 ) 10 ; 10 1250...
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20081ee110_1_hw5_sol-1 - Solution 1(a(b Solution 2(a To...

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