Lesson_16 - Chemical Equilibrium Chapters 16 and...

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Lesson 16 Chemical Equilibrium Chapters 16 and 19 (Petrucci et al.)
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Lesson 16 The nature of chemical equilibrium Consider the following reversible reaction
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Lesson 16
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Lesson 16
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Lesson 16 The equilibrium constant K c For the reaction CO( g ) + 2 H 2 ( g ) = CH 3 OH( g ) the equilibrium constant is defined as: Using the values given in Table 16.1: 2 2 3 ] ][ [ ] [ H CO OH CH K c = 5 . 14 ) 176 . 0 )( 138 . 0 ( ) 062 . 0 ( ) 151 . 0 )( 0753 . 0 ( ) 0247 . 0 ( ) 0822 . 0 )( 0911 . 0 ( ) 00892 . 0 ( 2 2 2 = = = = c K The value of the equilibrium constant is constant at a given temperature
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Lesson 16 Chemical eq. is reversible and spontaneous eq
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2 SO 2 ( g ) + O 2 ( g ) = 2 SO 3 ( g ) 3 . 5 ] 16 . 0 ][ 32 . 0 [ ] 68 . 0 [ ] ][ [ ] [ 2 / 1 2 / 1 2 2 3 = = = O SO SO K c 3 . 5 ] 16 . 0 ][ 32 . 0 [ ] 68 . 0 [ ] ][ [ ] [ 2 / 1 2 / 1 2 2 3 = = = O SO SO K c 3 . 5 ] 16 . 0 ][ 32 . 0 [ ] 68 . 0 [ ] ][ [ ] [ 2 / 1 2 / 1 2 2 3 = = = O SO SO K c 2 2 2 2 2 2 2 3 10 8 . 2 ] 016 . 0 [ ] 032 . 0 [ ] 068 . 0 [ ] [ ] [ ] [ × = = = O SO SO
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This note was uploaded on 04/13/2009 for the course CHEMISTRY 102 taught by Professor Soares during the Spring '09 term at Waterloo.

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Lesson_16 - Chemical Equilibrium Chapters 16 and...

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