Lesson_19 - temperature • A saturated solution is one in...

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Lesson 19 Van’t Hoff Equation The van’t Hoff equation can be used to estimate K c or K p at a given temperature, provided that K c or K p are known at some other temperature: - = 2 1 1 2 1 1 ln T T R H K K c c T 1 and T 2 have the units of K, and H is the enthalpy of reaction
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Lesson 19
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Lesson 19 1 2 1 2 1 2 2 1 2 1 2 1 1 0 ln 0 1 1 0 1 1 1 1 c c c c c c K K K K K K T T R H T T T T < < < < - - For exothermic reactions ( H < 0 ), if T 2 > T 1 Van’t Hoff equation agrees with Le Chatelier’s principle
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Lesson 19 Example 1 p -1
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Lesson 19 The solubility product constant K sp The equilibrium between a solid ionic solute and a liquid solvent is treated in a similar way to the one used to study chemical equilibrium:
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Lesson 19 Dissolution is dynamic :
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Lesson 19
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Lesson 19 Solubility, S The solubility of a solid in a solvent is the concentration of the dissolved salt in a saturated solution at a given
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Unformatted text preview: temperature • A saturated solution is one in which solid solute is in equilibrium with dissolved solute Lesson 19 Relationship between S and K sp for AgCl ( s ) = Ag + ( aq ) + Cl- ( aq ) • S moles of AgCl ( s ) ⇒ S moles of Ag + ( aq ) • S moles of AgCl ( s ) ⇒ S moles of Cl-( aq ) • S = [Ag + ] = [Cl-] • K sp = [Ag + ][Cl-] = ( S )( S ) = S 2 sp K S = Lesson 19 Relationship between S and K sp for CaF 2 ( s ) = Ca 2+ ( aq ) + 2 F-( aq ) • K sp = [Ca 2+ ][F-] 2 • S moles of CaF 2 ( s ) ⇒ S moles of Ca 2+ ( aq ) • S moles of CaF 2 ( s ) ⇒ 2 S moles of F-( aq ) • K sp = ( S )( 2 S ) 2 = 4 S 3 3 4 sp K S = Lesson 19 Suggested readings...
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