hw3 - PH 131 FALL 2005 HOMEWORK # 3 Assigned: 09/12/05 CL...

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Unformatted text preview: PH 131 FALL 2005 HOMEWORK # 3 Assigned: 09/12/05 CL ‘H m, 14,qu, 25,21, 50,53,‘8$)Hs’ In—-——_ 50 'SH EETS 22-1‘2 100 SHEETS 2244‘ 200 SHEETS 22-141 6 m 6.11:: position of an electron is given by r = 3.00:? — 4.00:2} + 2.0012, with s in seconds and r in meters. (3) What is [he clecu-on‘s velocity fir)? At r = 2.00 3, what is T" (b) in unit- vector notation and as (c) a magnitude and (d) an angle relative to the positive direction of the x axis? sz: “BAD-52- Vy -“-' "lel’é— so: Haw ' GIVEN: —h r—(j’F aOTT—‘f-O’f 'a J - \ +2.0 M 50 'SHEETS 22.142 300 SHEETS 2241.4 200 SHEETS 22-141 5H 4'? Hz” 5 - - , ‘ . GWEN: {- -.- .o?-(a.o*+z.o _ An ion‘s position vector is initially F“ =A5.0.' — 6.0j + 2m, ...' A J and 10 5 later it is r = —2.0i + 8.0j — 2m. all in meters. What ["1 = (—Z.o‘+8.0" $.01) is its avenge velocity during the 10 s? A ATE-1'2"“ =f05 “Os FIND: "ff F7719)" CALGULAT? 771'; DIEPZ—A-CEW '. A X :- 6270 —S.c5? + (92.0 +6.0): 4- ("Z-0"Z'DNL “'st 77g; Avmeé 1/510ch 4;, ewem 35>. H. In” AF—flflm V‘Z‘? M95 "05. 50 '5 HEETS 22 142 100 SHEETS 22-!“ 200 SHEETS 22-1‘1 e em— I5 E RM j _- ._ _ - _ _ ‘ I . . . t. - 1 A-9-—--—---=-_—..— . - . M The velocity T? of a particle moving in the xy plane i5 given @2553— _@'DT $01- ‘ +(g'o)fl‘ ' byv=(6.o:—4.0:1)i+s.oi.wim Vinmecersperwcmdand . '. - I (> 0) in seconds. (a) What is the acceleration when I = 3.0 s? . (b) When (if ever) is the acceleration zero? (c) When {if ever) is the velocity zero? (d) When (if ever) does the speed equal :‘§T[(é.OT—7.OT1>I‘\ n+(1’.o)fl 1;; $0 AT T: 3’06” 1 I 'Zé-[eaoQ = (49-0 “$093533? gt" 557’ 71:0" =0 AN}: SOLVE-FOR 77mg” : ;_.. ' A 1-1.. _ aggmflAu/‘r’ we? 55')— .Mfl: (so—gof)‘ 52. -0 W =0. fly Mb 0% ' é?_%OT Angenemfi 7:529. =5 ' '1”: "4 =msuaek 557” V(+)_=o 2 ' K VGA = (ao’rfi. 013)? ~1— (‘Ktoh ":0 ———§ 6'01-"L7‘01' :0 ) glo Vx \/y MUTE: wé'.‘ Omit-b Fm» A an»: Fore; “3mm. Vx = o “3121' V2 szgz. gauze, 252:9! . 1:)" £5- A com; MT) 9:: 7"»ng Lam. ANGU’EF-MNEUEL 3&7 A TIME TIM?“ 7745-. yawn T‘f _ ' 1-19 55m, 557” VG) 7- lom Am: Sou/5' FOIL 7mg: ' V0.3 : sz+vflz 20-251 - “4" .)(éad'-‘1.-OT2)1+ (9.037— : H31;— =29 Ce,d—e.or=)‘+ (gov—z.- l'oo . ' f-flifi!E—Zq .\=. 6.0 .. .01'2- 7- : . =2: 2.0;:1407‘2 = EEK—b =- 2-16 5.} “0-61 5 :7" 2.0?"— 301' :5 =0 T=@ Among-=12. .- ‘atcfl Eli-T” _W_ [C3 053+ SO'SHEETS . - 224 ‘2 100 SHEETS 22-11“ 200 SHEETS .22-141 6 AMMD . II I I _ _ ' 'H. Aballisshotfi'omdiegroundintomeair.Ataheiglxof 9.1 m. it§ veiodly is observed to be V = 7.6? + 6.13 in metemper second (i horizontal. j upward). (in) To what maximum height does the ball rise? (b) What total horizontal distance does ball travel? What are (c) the magnitude and (d) the direction of the bull’s ve- locity just before it hits the ground? - Fmsr Mu) flarwzé 1f— bot—47F REF? F764 7 z— mu, m; warm-rc- QALLULATE VAy, o RDM'A4B WEI WNW:- ME: V5:=\/.a;'il-Zb . my=,w.7%' wanna: AME-3.159 oBTAIqu'. ' Git/amt imntalwhmlhcpilotreleueany radudecoyfig-4-36).Thehor- mmdisnmebetwaentlnre- leanepointmdlhepointwhue mademym'itesfllegrumdis 7Wm(a)I-IOWlongisthethcoy infllenifiw)flowhighwasfl1e so 'SHEns 22.142 roe sum-s 21-144 zoo sneer: 22-14] 3 m 93-) An airplane, diving at an angle of 510° with the vertical, releases a projectile ar an altitude of 730 m. The projectile hits the groundS.(l)saherheingniease¢(a)Whatisthespeedofflle _ aircraft? (b) How far did the projectile travel horizontally during its flight? What were the (c) horizmtal and (d) vertical components of its velocity just before striking the ground? 04347: A REF? FM THE FINML. vsmcrrsr use '. E 7’0 wa 774g compomz-rs OF- I — :: u I i T: N w Vx "Vox +M ® M :11. m CH Hi1“) MVD:25.O% en's‘lo 0° @, Yoummwabanmwardawauwhnaspeedofzsnmxsm atan angle of 40.0” abovethe horizpntal (Fig. 4—35). Thequ is n.0mfmmdnmleasepoi1nof Maj-5'. U0 :Vo Mgo=.n:liz% dwball.(a}Hawfa:abovethe x .. _ .. M releasepoinldoeslhcballhilmc VD), :VD web-""f6-l 5 wall? (b)Wha1mthchorizmflal components of its (555’ MAW-x velocity as it hits the wall? me it hits.hasitpassed 3:2 ' the highesa POiIIl on its 1111- 59.445 Problcm28. “m? - gag , o _ =OU-h. 3“ , —-" pooATé.’ A 7357‘? WM}; r GIVEM' Xe” 0“- YD ? 5535 .. _x=z2.0m y = . $39 _J_ \élefiztg- v07: 29.1% Vo V,K :7 V\ :7, IV a): —O ’ 5?. AMTJO” m )I 5 b 7 5, .. flit. :— . 15‘. /_ = V°y_=---==l'5.ZM “$-09: W C? 5' y 257 K .mx HEM’H'T! Bv‘tj 12.0 m 4 W. quim1'oz.zu§ 4— M” PA.st THE #JG‘JES-‘i; “swag (E ‘ g3’“;%wufi? ngM 4:, E P- 50 sums 22-1‘2 100 SHEETS 22-1“ 200 SHH‘I'S 22—141 0% _H’3‘Ué’ 53) A boy whidsaminahodmnm circle ofradius 1.5mm: - atmmMmmmgwmmmm,mu-mm fliesoffhudmmallymduriku Ihegmmdafletmelingahofi- mldimmoflflmmisflnmglflmdeonhecenuipdfl acceleration of the 5m while in circular motion? - Au)?" bmufia ha”qu + Lam-r5 A My. FRAME: , 'x I \ I I \ R f a I H. To? WEN §IJ>£ VIE-u.) I Luz: rid/LL H.532) 70 FIN?) I917? VEE. GWEN ‘. . _ . __.__X.3 a .-—.— 0.9535 M: 77/15 Info Fm—fi‘zm. N61: 50qu F02. v, : W V =£='...=' - n 1- . I {5.7% Rush '_ - . 7:;- Mow use: mow T»; §PEED 9F Til-E BAIL WHILE .217" wA-s :rr-J UNIFORM OIRwLAP. N491 .— u ’2. £02.: grit: m: 50 SH! ITS 22-142 100 SHIRTS- 22-1“ 200 SHEETS 22-14! 09-" Gwen v=(2|exm’T“—_M " <33. The fast French train known as the TGV (Train a Grande Vi- 36005 tesse) has a scheduled average speed of 216 mm. (a) Ifthe train — go .‘L’L goee around a curve at that speed and the magnitude of the accel— - ‘5 eratton experienced by the passengers is to be limited to 0.0503, . a. = 0 . 050 what is the smallest radius of curvature for the track that can be W ‘3 tolerated? (b) At what speed mm the train go around a curve with _ a _t.o_o ten regiue to he at the acceleratiOIt.-limit? :7 (0' 0905633 3 l» am we: bolva T0 Fmb THE Mxmum $'PE£L Amwsb _G§|UEN: [— : Look.” : [’000 M ' SO SHE [75 22-142 100 SHEETS 22-ll4 200 SHEETS 22-141 /'_"‘ arm—f, us’ ' HKl/Qfi (‘5' An astronaut is minted in a horizontal centrifuge at a radius _GIVEN1 r— = 5.0M of 5.0 m. (a) What is [he aatmnaul’s speed if the eennipelal aceel- a = '7 o eralion has a magnitude of 7.03? (b) How many revolutions per ' 3 minute are required to this acceleration? (c) What is the __—_ 7' CC? % fl period of the motion? ' 51- @779 Fmb "THE «5 'EEb my? man BECAVSE 51°55!) I5 ALmn'fig 'PD‘SITWE. [5 o IND ‘H-E NUMBER. 0F REVOLUTIon P52 Mm. Rm» 5. WE U55 . —-—, = 1 N Pillob) oil TIME FOR I RayMTlDJ-«S g. a]: F.5qu mus. -fl-: |I| 1' 2m— =e> % = @«w E35673: = -————‘”““’E”~ 72m: 752mb 0F TfiE I“ 07b” 355- G’VEM 37’" F' 7—: 2%— : =®~M W's! L~ 471’. (nonuniudum - _ _ :...a-_ ._ - _ h+efla-Sn‘+am—6mh-fimf;&h 6”“ fi—5.°?+H'°J-6.0E r“. :Wfifigmmmmmm,“ i=a’o?*zp§ “Lob— '¢= 9'0? 13.03459"; Fr- Z :1; +3 :: (5.0 {\1-‘1-03 -B-D€.3 “(-IZaO'fi-Z- 3+3u&>+(‘f.0? 1-3. dig-FLO: A :0 13*; 46.033 41.032 fl 2;; IH = r- : ousacsorwa F. A @3325 Q m? TD Ema mam mmam v5¢wr~s 2:; TD on? we: “‘bo‘r” PM. r A .,.#;J-.£I W “60% mam-at ZE- Ig gMyby mg- gm?- VEC-TDX m we Z-bflt-U‘Q. . o ’ 3'35?“ng‘914 (‘31 6 —:- § 5} r313. -..- mm “(a = meme 1): AM A E k“ if‘l "A. ‘ K] E I mg = (Incowcaoyowevxsfix = ~7.c> WM sova Fox 6'. 24mf= "7-0 4:» fi =a'GTé-3 :fiyfl. Cog? : mag {fig-r weir ,_, S—I-O Zfigu7§e VMK (00—) M _ "5': m ms Z-AXJS. 50 SHIN! 22-142 IOU SHII'I’S 13 I“ m “I!!! 224“ ® a. -57; [L] 518. MWMInruwthqubiua won in a circle of radius 5.23 X 10_'" m unth a 248 MO WS.(a)Whuisdlsmlerwonofmeeiacmmnuus nudel?(b)Whuistbeperiodofthemotion? éIUEh-i ‘. Won to: U55: '0 Fm» THE AcuE x u. -__-. Ciooxngu 2.105 I" = 5.23x 10"" m V=Z-I$xro°_'5:t I’H l31 HW 6 Addendum "16 A 4.10 kg block is pushed along a floor by a con- stant applied force that is hor- izontal and has a magnitude of 40.0 N. Figure 6-26 gives the block's speedvversus timeras I I _ _ 19-1; the block moves along an x = = - - - ' axis on the floor. What is the 0 0-5 1-0 t." 5" __ 4,5- (M coefficient of kinetic friction ‘00 " EL between the block and the Fig. 6-26 Problem 16. ['0 floor? ...
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This note was uploaded on 04/13/2009 for the course PH 131 taught by Professor Wick during the Fall '08 term at Clarkson University .

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hw3 - PH 131 FALL 2005 HOMEWORK # 3 Assigned: 09/12/05 CL...

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