hw5 - PH 131 FALL 2005 HOMEWORK # S Assigned: 09/26/05...

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Unformatted text preview: PH 131 FALL 2005 HOMEWORK # S Assigned: 09/26/05 CLUE! 26,21,22,2 “IA 1, 35:00:75! .___' cks‘ ‘. use, 1-H; 50 SNEETS 22-]42 IOO SHEETS 22444 200 SHEETS 22-14] CH 5 “ a? . Hana @- car traveling at 53 km!!! hits a bridge abutment. A passenger —‘—"":_" , - car moves forward a distance of 65 cm (with respect to the: x D ' W‘- ‘ ' road) while being brought to rest by an inflated air bag. What mag- X -; GM' ,_._ a)" nitude of force (assumed constant) acts on the passenger’s upper _ m torso. which has a mass of 4| kg? Vex 1‘“ FOOD l 5 k t [9“ 36535 = l"! .73;- ' Vx 2 0 £2:— 4x = /_x z ._ mwfib ... M _ H l H: 40 Mar l of: N07?! '14 ; ‘1: o #175 '77; _. ' 12511904 IRE AG ‘- / Bab .‘b/ .--' I “A LL}! EDE- LJSé’: Mai-EMS 2. N 2133M“): I r F," i...— -— -rx __ t can TMST an 1321:; Agnwmf IHPMEQ CD " . 50 SHEETS 22-142 IOO SHEETS 22-144 200 SHEETS 22-141 29 A firefighter with a weight of 712 N slides down a venical pole with an acceleration of 3.00 W53. dimmed downward. What an: the magnitudes and directions of the vertical forces (a) on the firefighter from the pole and (b) on the pole from the firefighter? F7125?“ 32M» Hus; Beost LIAM Fa??— fizgmmz: "\FM fixer-7213 3/ 304g ogw 32:53:. mam (Fnuanm-ML- FOR-c5. .4- N” " w m: -—> m = Y 4 (Mb mm; 7251:. mans) fig}— : 12-3 ta non M51070»; 2&5”: ZIP; =ma\ fP—wxa = MA), F} = MGM-h .— 77}; RM HERVE—.5 3V MHFENGIHE‘R czar-.5 WEI-E" Pal/E I6 ALE-o H0 £1: Bur hxfiea‘ab “DOMNLLJN'ZL A MEN-18F... 50 SHEETS 22-142 IOU SHEETS 22-l44 200 SHEETS 22-h“ cHS '_ — _ L" muses: = hisoxfo"N @ .. 30 ‘ "“ A car I at weighs 1. x to N is initially moving at a speed _. f 40 kmfh when the brakes are applied and the car is brought to X 0 i o M a stop in 15 m. Assuming that the force that stops the car is con- X = M slant. find (a) the magnitude of that force and (b) the time required [an m for the change in speed. if the initial speed is doubled. and the car VDX = (10 "' experiences the same force during the braking. by what factors are M '(c) the stopping distance and {d} the stopping time multiplied? V); = 5 (There could be a lesson here about the danger of driving at high speeds.) a )s. z . ,— '1 9;; 7744; THE FEQQ"57> WE ' mat. B‘v’ A :V A __"2—V; ._ ©$)/X/ ox..+V XII—59 ZFuEbOUBI-E V0,, '5? new' "'——1 — 1;”: A :53. 7;; = etc-"'5- ..~.r 6.1757114 m: 515 "’35!!! I SD SHEETS 22 142 IN SHEETS 22444 200 SHEETS 22-14] @9 .24 A block is projected up a frictionless inclined plane with initial v0 = 3.50 mfs. The angle of incline is I9 = 32.0”. (a) How far up the plan: does it go? (b) How long does it take to get there? (c) What is ils speed when it gets back to the bottom? 55!“ i i i I I F f 50 SHEETS 22-142 100 SHEETS 22-144 200 SHEETS 22-141 39 "t sphere ofmasa 3.0 X 10“ kg is suspended from a cord. A steady horizontal breeze pushes the sphere so that the cord makes 9 a constant angle of 37° with the vertical. Find (a) the magnitude of that push and (b) the tension in the cord. seat In» m ‘3 "" wE cw ‘Ppuc. .r "1997— Epcot-115' Fog “'- bo AT 0 JDUTO d:- “-“ 3112.241— FTLDM Em.§§21 I fif—‘fl. :ntt ®4 /" ME) 51 5.91.. ME— FOR. a; M 50 SHEETS 22 142 100 SHEETS 22-144 200 SHEETS 22-1-3] @ 3.5 An elevator with a weight of 27.8 IN is given an upward G “'5 53'. acceleration of 1.22 mst by a cable. (:1) Calculate the tension in the cable. (b) What is the tension when the elevator is decelerating w = "‘3 '3- 2.7300 N at the rate of 1.22 mfs2 bul is still moving upward? M a. = In 2-2 '—"i 5 5c:- '. ——— EmAr-ok- Is. Movwc. QWE- : (2300M34-(z'831kj = fl _ SO SHEETS IOO SHEETS 22-144 200 SHEETS 2244! 22-142 3 IMHO \ ID kg monkey climbs up a mmless rope that runs over a frictionless tree limb and back downto a l5 kg package on the ground (Fig. 5-43). (a) What is the magnitude of the least accel- eration the monkey must have if it is to lift the package off the ground? If, after the package has been lifled, the monkey stops its climb and holds onto the rope, . what are (b) the magnitude and Gl‘uE’I'QI M -._—. [0 k3 (c) the direction ofihe monkey's I acceleration, and (d) what is the M2 = 15 lensinninthc rope? ssm 3 ‘ q'g "5—2 74mg; mm. m. BE MFIEA bomb—E Tfi “42,3 J THE finial-y; p0,»? Occult/MC.- mHEM mg 41‘ («J/Hz.” ” P0! 10'!— a-y :4Mu 1:50;). ,C‘RoM Thus we— cm 955' MT 7595 MQMLEV cm .2ch. “1;:sz ‘T‘ $lMPL‘f 115’ IM. m5, Act-ELELATIOAJ 4y. .5) aoLl/JMGI- BY SEW/Nev (DEGUfld—TDQ) maammlm, -, Du.) ma“ IM'FZJ {ADHERE wx ‘>-IM ' 'DiR-CF ACC‘ELERH Ir UPI/CAM Toad—IMMAKT: a), (m l +wz> = :1 (ML-M.) “- 2: 2"“. '2 \‘t — ED H 7 Cid“; 6} 4% I0 Fimé —*: fingLz gafi-UE cw?— FD/E TAAJD use—fl“ '. T: W Ay+ =n11' @—\> :C 33 A ; SO SHEETS 22-142 100 SHEETS 22-144 100 SHEETS 22441 pulley to a second block of mass m: = 2.30 kg hanging vertically (Fig. 541}. What are (a) the mag- nitude of the acceleration of each block and (b) the direction of the acceleration of the hanging block? (c) What is the tension in the cord? ssm Itw m To 6577715 720 FM Now Ah ‘3 Mrwa (ED-+7: Nora“: EQM.,® BOT howl-b BE H SQ . A block of mass m, = 3.70 kg on a frictionless inclined plane f angle 30.0“ is connected by a cord over a massless, frictionless AND (D To £44mme 7": _m'3 "fl/“2,3 : WIKX +Mzax fig (Infill/e.) : 05 (m2;- SIruc-E' at: 5.325 ou’l‘ Poggflugj 771E: ACLELEMWOM 3F ML .Le In 7744»: 7’05. x—tmzv 072.. bomwwam. 77:5 FIND T Elnang SOLVE (D c?- Q; FOR- '7'" ANb USE A)! .' Mng'flA = taming?! mAs Mo'i— MEEbEb I» "THIS T’RoBL-EM GIVE“: M1 =3.7D M2,: 2.30 e = 30.0“ a =9.‘8’§§- HE E F'oR. m 35 5mm. margugou o E NOTE—2 77m, 1-; Mar 7796' cam—5" wAH’TD ' MES mHEzE 77:5 25?. _ one FOR M '- E—Lo sou-E 60¢» A PROBLEM, Bur non-4c; 1::- 7795 Low :5 ommizATrouALu-r’ MICE-.— - ' MD M; cum. In HAVE 7741:" SM: nails—'4‘ tans- CASE" :2» THE m5. 07‘ x—DJR. N572: w1y=wme=mgmé3 Nix :N&9= M3 1M, Ale) 7: “‘ :flnsmafi- fins-.4352- Ab unE-IuHfi-Ubéb 3:72.107an r—-——¥/ 50 SHII'I'S 22-142 100 SN“?! 22 I“ 200 SHEETS 22-h" 168. A weightmious penguin with a mass of 15.0 kg resls on a bathroom scale (Fig. S—4l). What am (a) [he penguin's weight W and (b) the normal force N on the penguin? (c) What is the reading on the scale. “aiming it is calibrated in weight units? — E Mugs w $ Ed Us”): I: newly” : 6-" "in—W ; an - ~,- 2. m 7:“..JZ—N: :- TFl. f—E'mrfiro‘e" }r="‘ M: M|:q'gkfi “2:. m3=5'.5k3 T.==I‘HN .3 w: ---:’ N: 1.7; gnaw-mug i?— LAwFoKM‘. I l! 73"“33 =0 ...
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This note was uploaded on 04/13/2009 for the course PH 131 taught by Professor Wick during the Fall '08 term at Clarkson University .

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hw5 - PH 131 FALL 2005 HOMEWORK # S Assigned: 09/26/05...

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