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# hw6 - PH 131 FALL 2005 HOMEWORK 6 Assigned 7,149.1...

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Unformatted text preview: PH 131 FALL 2005 HOMEWORK # 6 Assigned: 10/03/05 7,149.1, 2g,2={,1<?; W: S" Cké - L0! 324 50 SHEETS 22-141 190 SHEETS 22-144 200 SHEETS 22441 @A 3.5 kg block is pushed a 0113 a horizontal ﬂoor by a force Fof magnitude 15 N at an angle 9 = 40° with the horizontal (Fig. 6—26). The coefﬁcient of kinetic friction between the block and the ﬂoor is 0.25. Calculate the mag- nitudes of (a) the frictional force an the block from the ﬂoor and (b) the acceleration of the block. mom: REFFMME; f.— Fy’ erme ka 4246 -.21 . _, - _ GEVEM- vow—mu a!) Black a in Fig. 6-29 weighs M5 = 0’35 7! N. The coefﬁcient of Staiic ' _ o ._. ﬂ. friction beLWCen block and table ' _ ' % q'g S L is 0.25: assume that the cord be- _ _ t... ‘4’ 053-5 4 tween 3 and {he knot is horizon— I "‘ 5 .1- Ax " o 52 ”-5 .I *5 tal. Find the maximum weight of .- 11 STAT! C blockA for which the system will A); — D 51. Eaum EN” be stationary. 55m in ”333 @ zmvﬁéxg Q‘s-719))2—19w AHB.D.F0R£A¢H BMAMAWE Jumcj’azl; 'POILW'. N - . . NA 1451‘!» IS- W‘m Siva-z uJE‘ Ana us: I. 13-!“ 1am 22-!“ ‘m‘lm ”all" ® . 2,2 "1 Fig. 6—3l, two blocks are co nected over a pulley. The NY- : 0 :0 masz; of block A is ID kg and [he 6 = 30 cueﬁicient of kincIic friction bc- _._. qu --£ tween A and the incline is {1.20 . a 5 Angle B of the incline is 30”. Frictinnless, Block A slides dawn the incline "mm“ Pun”? . m : ? at constant speed. What is the I B mass of block 8'? 0257' 40mm 25? RAM mob mum F173,. ’ OTE: 51:44:": BOTH 8W5 )4ng N AT_C'DL2I§7F. graze!) m WIS "Micah-EM '- , BEE WAX: WA we: wiggle {—39 55.7 @‘EQUﬁLTD g) 331: w l . 502.425 Flak. MB: " W T73” 71 w WW9) - 7’: W3 =0 a -""‘51W<“9<“*“‘9> =69... AL. 50 SHEETS 22-142 100 SHEETS 22-144 200 SHEETS 22-141 9? 164-16 — 2f. . Haw. . . GWEN- WA:ioz.N 3}) Body A in Fig. 6-3! Weighs 102 N. and body 3 weighs 32 N. N _._. 32 N The coefﬁcients of friction between A and the incline are H, = 0.56 B _ 5‘: ' and m = 0.25. Angle ﬂis 40°. Find me acceleration ofA ”(3)24 #5 '0’ is inilially at rest. (b) A is initially moving up the inclinc. and M"- = 0.2))- (c) A is initially moving down the 9 =1 I1 0 l incline. m m __ Frictionless. g '" c755 51 masslcss pulley _ NoTE'. Anion Lo}: Do MF-HOH-‘D THE - biWDH ﬁATW’b swam“ w: J ' meT'TO “‘25er .274. 5g!» 4.»;me CHOOSE (M55) A Alﬁacrb_ ' A”b \$7M SMUTJOHgaa—L'Lé? ,2): so; m-conxéc on - - ' u MHE 5-- m‘efygwﬁt 2‘3””: .1 _ Nova: sum; fr rage—LEASEb Fzmm ' F857: u-JE D0917" KMDMJIFWE \$5,573” pol-LL Serl-‘f' ”ELM“ AS I5 (57“,ij any: ﬁC—WM‘T’ 51 lat-T: ’ STATM. 7-3 9445.. “HE MIN ﬂ KECQ3_T0LELE7-IT‘FWA 1A.. "71-41514 p05 CDHPNLE '77:"; MIT}! 'wMT we Ate—WNW“! EMUE FUR—ﬂ, WAX: WAM 9 _ WA), = w Lad-Q ﬁ——-—-_— “8) game: svemM STA-rats: If; 7" W — éﬂﬁ44 = ‘ - ' E's : 5 W4 ©7795 ~56. slam mbrcAraQurr mg- - —z +W _._. ' 4f 7:11:41". Fail-CE ALWAU—Y Parms 0?: .5! B _: ._.'7_'>l1 N. 1.1:??gléﬁé‘mgw owns T0 ACQEL, b- Am: DA sTmc. Ham". - - @ an Thus. SYsIEEM 1'25: , AMovap :— N: Wm9=...: N . . ”WE {fem/“e Ms A - ‘2‘" ~F-—b - Mb 794:: mil. - 7H5" 55372 f "hm . ' 2'52: 5 ' {55\$ BECOME! ' 12-5le - STATJL. -=3> 615925: (D—bﬁwAQB—ﬁ: 1': MA“; 1' Lama . c3 = W;- ﬁ'WAﬁe'f/(AkkkzMAa-x __ I e' 'Ngwmaua c 6'26 . Hﬁw’ GIV£N'- A 5 WIN 2%. In Fig. 6-25. blocks A and B . ha I: weights M44 N and 22 N. " W B : 32' N I ' l () De ' [h Frictionlc'm M5 =-O. 5 respective y. a lemme e . - ' _ :0 ,] minimum weight of block C [0 I ”male“ Punt“. MB.- ﬂ. 1 keepA from slidingifp,bctween % " 3'3 5:. A and the table is 0.20. (b) Block C suddenly is lifted off A. What ' is the moderation of block A if - ,u.‘ belwecn A and the table is 0.15? 55m FWD" (a) NC 13 KEEPH' ______.._.-—- FROM SLIDING-I U”) Amalgam-Hm 04 A ”La" C. If) {EC-HA (bi/P' _ Mu.) ﬁg}; Fang/dim; Mug: (my cup“; AREFFE-QME Far—EACHB - . _ 7] . .A convEMJEM—r way) To be “rm?- :5 N T'o pet-r we MF- Fm fox. moan F3, CK~AX\$) SIM?LH’ Db Ni “£xr£bx:<=*5"oF THE “-57".— FMS Foil BLOCK. At. 77mg, :7: 77145 31,0446 {L x vbne. M" - Nom‘éot—Vé‘ 779:5 FOZ We? y- “4.5 “My“;éy/Ugmcé :0 72-2 1:5?) 2 Am 2 ME- N WI}: “4 S ’5 -—— _— WV #5. . ECDME: . ' ail In! W9. 0? w£}6H_: EQUATJDbQ": M o "TL/elk M = ”4451;: puTE: W¢ twat: = __.E. AMA) _ ( m ‘3 9 N = “A1 -_ C i}- "7? “5‘3 '5 ”.154“ ' ﬂ ”‘7 AW Th/HkMAj :MA a); . HMAB‘B THE, To (3) 71:2 gnawing; Z5 a (Wig/1&4 ‘32 1 (MA “‘41: ”9‘ ' to a hanging cylinder of mass M by a cord through a hole in the table (Fig‘ 6-37). What speed keeps the cylinder at rest? 55m FIGURE 6-45 Exercise 5?. ”In in": man mm @M S0 5_ G) 4495(3) game, WEMMIM.. 9' WE Wﬁ : MI I“ U .. 5f .__.._ _§H6 ._ @945 shown in Fig. 6-39, n .4 kg ball is connected by means of mm massleSS strings to a vertical, rotating rod. The strings are tied to the rod and are _ taut. The tension in the upper string is 35 N, “Draw the free- body diagram for the ball. What are che tension in the lower Slring lttnglh ._.--- = 1.?!) m much / :7 3S N string, (b the net force on the ﬁ ‘\ anling rod ball. and w the speed of the " ball? 55m it»: V II 31 i 0 5 .- 50 SHEETS 22 l42 100 SHEETS 22-144 200 SHEEI’S 22-14! ® . 5W— e=30° 11:4.w28 5mm». 1 i T Am - \ ‘n E; (B I E’r CD 3. n O A.; J ' - Am. ”Mmng-AL Act—EL. hum-s ;0L._J_’_~ __ IE 56’;me 0F QM. PATH 60 ME) Halo; . POINT5 Towkﬁ-b CENATEK 5F- umc. PATH A"; “ELL. . . ' FMET:T;'¢:¢_B+7EMB :... =® ANS. 0P." 2. ; -.__.—- ﬁne-IT” z Mi‘m M BUT wE' bog I Know V" 50 SHIEFS 22-142 100 SH [£15 32- I 44 200 SHEETS 22-14] ® coeffment of static friction between black and table is (1.52 ta) What is the magnitude of the horizontal force that will. put start the block moving?.{b) What is the magnitude or :t I'uicu acting upward 60° from the horizontal that wit! just slurl lltt.‘ hltwl-t moving? (c) If the force arts down at 60" from the hortmntui. how large ZUI’. Art i I kg block of steel Is at rest on a horizontal Itthln: The can its magnitude be without causing the him-k in move? my: A6 7145 AHMED FOME(F)J:\$ Item-45525) 7W5: 57747;; chx. Fax—6565;) Ari-\$0 maze-Asia‘s. I" 0P7DSIWDM. Fx =F‘m6 F rFizte N075: THE Mas-~95??— #524? c. _BE ﬂown“) :54 A SIMILAR. ' Mane-7:12. As, was “Dong ‘ PAP—TEX} 542;th; THE SAME 55210.1 (1097' use”. eneo") : ﬂLv _ .._= ,F metv/ogMa— -2 -' non-bu- !2 1‘2 100 SHII'I‘S 22-144 200 SHEETS L“) 323. A circular curve of highway IS designed for trafﬁc movmg at 60 kmfh. (a) If the radius of [he curve. is ISO m. whnl IS the cornea angle of banking of the road? (b) If the curve were '10! banked. what would be [he l'l’liﬂllTlul'Tl coefﬁcient of friction be- tween Iires and read than would keep trafﬁc from skidding all this speed? I'Tﬂou’f' F71 #6170 ...
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hw6 - PH 131 FALL 2005 HOMEWORK 6 Assigned 7,149.1...

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