ECE474S09_Lecture04 - ECE 474: Principles of Electronic...

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ECE 474: Principles of Electronic Devices Prof. Virginia Ayres Electrical & Computer Engineering Michigan State University [email protected]
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Lecture 04: Physical Structures: Hexagonal systems: CNTs Introduction The Basis Vectors: a1 and a2 The Chiral Vector: Ch The Translation Vector: T The Unit Cell of a CNT Number of atoms Packing fraction/Density => Areal Density Nearest neighbor distances
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Width: Ch called the Chiral vector Length: T called the Translation vector T X C h = the area of the CNT Unit Cell Note that T and C h are perpendicular. N => number of C atoms
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The Chiral Vector C h Example: Prove that the magnitude of | C h | is a n 2 + m 2 + mn C C h
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| C h | = arc length = θ r t d t The Chiral Vector C h Defines the CNT tube diameter d t r t Example: Find the nanotube diameter for a (10, 10) CNT. Answer: d t = ( 3 1.44 Angstroms) 10 3 / π = 13.75 Angstroms 1.4 nm
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T: Note that T and C h are perpendicular. Therefore
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This note was uploaded on 04/14/2009 for the course ECE 474 taught by Professor Ayres during the Spring '09 term at Michigan State University.

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ECE474S09_Lecture04 - ECE 474: Principles of Electronic...

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