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Unformatted text preview: adamkiewicz (ja28724) motion in one dimention Morozova (11102) 1 This printout should have 12 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 2) 10.0 points A person travels by car from one city to an other. She drives for 32 min at 77 . 9 km / h, 13 . 4 min at 110 km / h, 38 . 9 min at 49 . 9 km / h, and spends 12 . 1 min along the way eating lunch and buying gas. Determine the distance between the cities along this route. Correct answer: 98 . 4652 km. Explanation: Distances traveled are x 1 = v 1 t 1 x 2 = v 2 t 2 x 3 = v 3 t 3 Then the total distance traveled is x = x 1 + x 2 + x 3 = (41 . 5467 km) + (24 . 5667 km) + (32 . 3518 km) = 98 . 4652 km . 002 (part 2 of 2) 10.0 points Determine the average speed for the trip. Correct answer: 61 . 2854 km / h. Explanation: And, time spent is t = t 1 + t 2 + t 3 + t other = (32 min) + (13 . 4 min) + (38 . 9 min) + (12 . 1 min) = 1 . 60667 h . Hence v av = x t = 98 . 4652 km 1 . 60667 h = 61 . 2854 km / h . 003 (part 1 of 2) 10.0 points An electron in the cathode ray tube of a tele vision set enters a region where it acceler ates uniformly from a speed of 51600 m / s to a speed of 3 . 21 10 6 m / s in a distance of 2 . 37 cm. What is its acceleration? Correct answer: 2 . 1733 10 14 m / s 2 . Explanation: Basic Concepts: Constant acceleration The kinematics equations v f = v o + at v 2 f = v 2 o + 2 as Solution: Taking the direction of motion to be along the x axis, the second equation yields a = v 2 f v 2 o 2 x = ( 3 . 21 10 6 m / s ) 2 (51600 m /...
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This note was uploaded on 04/14/2009 for the course PHYS 111 taught by Professor Moro during the Spring '08 term at NJIT.
 Spring '08
 moro
 Physics

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