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Unformatted text preview: 2> grams N 2 • P V = n R T • n = (PV)/(RT) • n=(10 atm * 0.5 L) / (0.08206 L atm/mol K * 298 K) • n=0.204 mol • 0.204 mol N * (28.02 g/mol) = 5.7 g N 2 hat is the identity of a gas with What is the identity of a gas with a density of 1.428 g/L at STP? • Density > Molar Mass > Identity of gas • M=DRT/P • M=(1.428 g/L * 0.08206 L atm/mol K * 273 K) / (1 atm) • M=31.99 g/mol 2 /m l x n • 32 g/mol=oxygen...
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 Spring '08
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 0.5 L, 5.7 g, 0.50 L, 28.02 g

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