012109_lecture

# 012109_lecture - Gas Rxn Stoichiometry Effusion/Diffusion...

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January 21 st 2009 , 2009 •Gas Rxn Stoichiometry •Effusion/Diffusion •Real Gases

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CO 2.0 L H 2 0.50 L 3.0 atm 2.0 atm CO (g) + 2 H 2 (g) -> CH 3 OH (g) at 0C What is the pressure of CH 3 OH produced? What is the total pressure in the vessel after the reaction?
CO (g) + 2 H 2 (g) -> CH 3 OH (g) at 0C Pressure of CH 3 OH after reaction: Mols CO and H 2 -> limiting reactant -> mols CH 3 OH -> pressure CH 3 OH PV RT PV/RT PV=nRT, n=PV/RT n CO =(3.0 atm*2.0 L)/(0.08206 L atm/mol K * 273 K)=.268 mol This amount of CO would produce 0.268 moles CH3OH ( * )/( * ) l n H2 =(2.0 atm*0.50 L)/(0.08206 L atm/mol K * 273 K)=.0446 mol This amount of H 2 would produce 0.0223 moles CH 3 OH-Liming reactant P CH3OH =nRT/V=(0.0223 moles * 0.08206 L atm/mol K * 273 K)/ 2.5 L=0.20 atm Total pressure after reaction: CO was the non-limiting reactant some will be leftover CO was the non-limiting reactant, some will be leftover Producing 0.0223 mol CH 3 OH will require 0.0223 mol CO 0.268 mol CO – 0.0223 mol used = 0.246 mol leftover P RT/V 2 20 P=nRT/V=2.20 atm Total pressure=P CH3OH + P CO =0.20 atm + 2.20 atm= 2.40 atm

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