Results and Calculations

Results and Calculations - the 25mL water solution M 1 V 1...

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Results and Calculations: 1 st titration (NaOH) 2 nd titration (NaOH) 1 st titration Concentratio n Salicylic acid (Molarity) 2 nd titration Concentrati on Salicylic acid (Molarity) 1 st Titratio n Partitio n Consta nt 2 nd Titratio n Partitio n Consta nt Avg. Titratio n Partitio n Consta nt 25mL water 0.5mL 0.0158 1.333 75mL Octan ol 2mL 0.0211 50mL water 0.25mL 0.0158 0.25 50mL Octan ol 1mL 0.00396 How the concentration of salicylic acid was found for
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Unformatted text preview: the 25mL water solution M 1 V 1 =M 2 V 2 0.07919Moles/L X (0.5mL X 1L/1000mL)= ? X (25mL X 1L/1000mL) ?= 0.0158 M How the Partition Constant was found for the 25mL water and 75mL Octanol solution Concentration of octanol/ concentration of water 0.0211/0.0158=1.333 How the average partition constant was found for the 25mL water and 75mL Octanol (1.333+ X)/2+ Y...
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