Exam 02 - Su Yung Exam 2 Due 3:00 pm Inst FAKHREDDINE This...

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Su, Yung – Exam 2 – Due: Oct 19 2007, 3:00 pm – Inst: FAKHREDDINE 1 This print-out should have 23 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. The due time is Central time. Each question is worth as assigned. 001 (part 1 of 1) 10 points N 2 has a bond order of 3 and O 2 has a bond order of 2. Based on this information, choose the response that best completes the following sentence, in the order listed. N 2 is (less, more) stable than O 2 , and has a (larger, shorter) bond length and a (higher, lower) bond en- ergy. 1. more; shorter; lower 2. less; longer; lower 3. more; shorter; higher correct 4. more; longer; higher 5. less; shorter; lower Explanation: The higher the bond order, the more sta- ble the molecule. Stable bonds have a high bond energy since they are hard to break apart. As bond order increases, the bond length gets shorter. Triple bonds have shorter bond length than double or single bonds. 002 (part 1 of 1) 8 points Assuming these can all be made, which would have the largest diameter? 1. Cl 2+ 2. Cl 1 - 3. Cl 1+ 4. Cl 2 - correct 5. Cl 0 Explanation: All of the species have the same number of protons. As the number of electrons increases, the attractive force per electron decreases and they are found farther from the nucleus, re- sulting in larger particles. 003 (part 1 of 1) 8 points The correct formula for iron(III) carbonate is 1. Fe 2 CO 3 . 2. Fe 3 (CO 3 ) 2 . 3. Fe 2 (CO 3 ) 3 . correct 4. Fe 3 (CO 3 ) 3 . 5. FeCO 3 . 6. Fe 3 CO 3 . 7. Fe 2 (CO 3 ) 2 . 8. Fe(CO 3 ) 3 . Explanation: The iron(III) ion is Fe 3+ ; the carbonate ion is CO 2 3 - . Three CO 2 3 - are needed to balance the charge on every two Fe 3+ . (This gives a total anion charge of - 6 and a total cation charge of +6.) The formula is Fe 2 (CO 3 ) 3 . 004 (part 1 of 1) 8 points Which of the following elements has the high- est ionization energy? 1. P correct 2. Si 3. S 4. All would have equal ionization energies. 5. Cannot determine without more informa- tion. Explanation: P = [Ne] 3 s 2 3 p 3 neutral atom has additional stability due to the fact that its outermost or- bital is half-filled (3 p 3 ). This is referred to
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Su, Yung – Exam 2 – Due: Oct 19 2007, 3:00 pm – Inst: FAKHREDDINE 2 as half-filled stability. In such a case the ion- ization energy is higher than what would be expected for a simple left-to-right trend across the periodic table. If such a simple trend were followed, we would expect the ionization en- ergy of P to be between Si and S. In reality, since P has added stability due to a half-filled orbital, it takes more energy to remove an electron from P than from Si or S.
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