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Homework 09

# Homework 09 - ycs73 Homework 9 Fakhreddine(53605 This...

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ycs73 – Homework 9 – Fakhreddine – (53605) 1 This print-out should have 11 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points The volume of 0.100 M NaOH required for the titration of 100 mL of 0.100 M CH 3 COOH to the equivalence point would be (larger than, the same as, smaller than) if the acid were 100 mL of 0.100 M HCl. The equivalence point for the HCl titration would come at (a higher, a lower, the same) pH than for the CH 3 COOH titration. 1. smaller than; the same 2. the same as; a higher 3. larger than; a higher 4. the same; a lower correct 5. larger than; a lower Explanation: [NaOH] = 0.1 M [CH 3 COOH] = 0.1 M [HCl] = 0.1 M V HCl = 100 mL V CH 3 COOH = 100 mL The amount of acid required to react a given number of moles of base depends on the total number of moles of H 3 O + the acid can provide. 100 mL of 0.1 M CH 3 COOH and 100 mL of 0.1 M HCl both provide 10.0 mmol H 3 O + . However, because CH 3 COOH is a weak acid and HCl is a strong acid the pH at the equivalence points will differ. In the case of HCl the spectator ions present do not hydrolyze and the endpoint pH is 7. In the case of CH 3 COOH, the CH 3 COO tritra- tion product hydrolyzes, producing OH ions which raise the pH above 7.

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