Experiment 6 Report - Experiment#6 The Addition and...

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Experiment #6The Addition and Resolutions of Vectors:The Force Table14 October 2015PAGE 1
Objective1:The object of this experiment is to:1.Add a set of vectors graphically to find the resultant2.Add a set of vectors analytically to find the resultant3.Appreciate the difference in convenience between using graphical and using analytical methods of vector addition.1 Jerry D. Wilson and Cecilia A. Hernandez, Physics Laboratory Experiments Revised Eighth Edition 77PAGE 2
Experiment 6Data Table2Data TableForces (gN)Resultant R (magnitude and direction)GraphicalAnalyticalExperimentalVector additionIF₁ = (0.200)g N, θ₁ = 30°F = (0.285)g N, θ = 75°F = (0.283)g N, θ = 75°F = (0.275)g N, θ =75°F₂ = (0.200)g N, θ₂ = 120°Vector additionIIF₁ = (0.200)g N, θ₁ = 20°F = (0.300)g N, θ = 25°F = (0.304)g N, θ =25.3°F = (0.300)g N, θ =45°F₂ = (0.150)g N, θ₂ = 80°Vector additionIIIF₁ = Fₓ = (0.200)g N, θ₁ = 0°F = (0.250)g N, θ = 37°F = (0.250)g N, θ =36.9°F = (0.250)g N, θ =37°F₂ = Fᵧ = (0.150)g N, θ₂ =90°VectorresolutionF = (0.300)g N, θ₁ = 60°Fₓ = (0.150)g N, θ = 0°Fₓ = (0.150)g N, θ = 0°Fₓ = (0.150)g N, θ = 0°Fᵧ = (0.260)g N, θ = 90°Fᵧ = (0.260)g N, θ = 90°Fᵧ = (0.260)g N, θ =90°Vector additionIVF₁ = (0.100)g N, θ₁ = 30°F = (0.130)g N, θ = 163°F = (0.131)g N, θ =163.1°F = (0.130)g N, θ =163°F₂ = (0.200)g N, θ₂ = 90°F₃ = (0.300)g N, θ₃ = 225°Vector additionV14 October 201514 October 20152 Jerry D. Wilson and Cecilia A. Hernandez, Physics Laboratory Experiments Revised Eighth Edition 83PAGE 3
Data Analysis3Types of EquationMeaningsVariablesR = (scaling factor) (measured length)Used to determine the magnitudeof the resultant vector graphicallyR2=A2+B22ABcosγUsed to determine the magnitude

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