CHAPTER_5_TEXTBOOK_SOLUTION

CHAPTER_5_TEXTBOOK_SOLUTION - 1 EE 101 Introductory...

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1 EE 101 Introductory Electrical Engineering Chapter 5 Homework Solutions 5.1 Determine the decimal values for the following unsigned numbers. a) ( ) ( ) 0111011110 0 1 1 1 0 1 1110 00 0 2 5 61 2 86 41 6842 478 2 10 = •+•+•+•+•+• +•+•+• = +++++ + ++ = ++++++ = 222222 + 2 2 2 2 222 2 + 987654 3210 876 4321 b) ( ) ( ) 1011100111 1 0 1 1 1 0 0111 512 0 128 64 32 0 0 4 2 1 743 2 10 = = ++++++++ = + + +++++++ = + 2 2 2 2 20 2220 + 0 9 765 210 c) ( ) ( ) 3751 3 7 5 1 37 5 1 1536 448 40 1 2025 8 10 = •+•+•+• = + •+•+• = +++ = 8888 512 64 8 1 d) ( ) ( ) A25F 16 16 16 16 16 1 321 0 16 10 10 2 5 15 10 4096 2 256 5 15 40960 512 80 15 41567 = = •+ + •+• = = e) ( ) ( ) F0F0 16 16 16 16 16 32 10 16 10 15 0 15 0 15 4096 0 15 0 61440 240 61680 = = +•+ = + =
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2 5.2 Determine the decimal values for the following one’s complement numbers. a) ( )( ) 0111011110 478 11 0 ' s complement form = + b) ( )() ( ) ( ) 1011100111 0100011000 12 12 12 256 16 8 280 843 2 10 10 ' s complement form ,C =− •+•+• ++ c) ( ( ) 1111111110 0000000001 12 1 0 2 10 ' s complement form ,C 5.3 Determine the decimal values for the following two’s complement numbers. a) ( ) ( ) ( ) 0111011110 011101 1110 00 0 256 128 64 16 8 4 2 478 2 10 =+ +•+•+•+•+• +•+•+• +++++ + = ++++++ 222222 + 2 2 2 2 222 2 + 987654 3210 876 4321 b) ( ( ) 1011100111 0100011001 12 12 12 12 2 8 1 22 8430 10 10 ' s complement form ,C •+•+•+• = c) ( ( ) 1111111110 0000000010 2 1 10 10 ' s complement form ,C =
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This note was uploaded on 04/29/2008 for the course EE 101 taught by Professor Gutschlag during the Fall '07 term at Bradley.

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CHAPTER_5_TEXTBOOK_SOLUTION - 1 EE 101 Introductory...

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