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Exam_3_key - Exam 3: Bio 101 (45 pts) 14 November 2007 Name...

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Exam 3: Bio 101 (45 pts) Name _______KEY____________ 14 November 2007 Questions 1-5 refer to a female aphid capable of reproducing either mitotically (asexually) or meiotically (sexually). 1. (1 pt) A diploid female aphid with 24 total chromosomes produces offspring mitotically. How many chromosomes will her offspring have? 24 (diploid from mitosis) 2. (1pt) Later in the season she produces eggs by meiosis, mates with a male, and produces offspring via sexual reproduction. How many choromosomes do her eggs have? 12 (haploid from meiosis) Crosing over 3. (2 pts) You recognize that her sexually-produced offspring ought to be more variable than those produced by mitosis. Name two events that happen during meiosis that can lead to variable offspring. Independent assortment 4. (2 pts) Given the option to reproduce either by mitosis or meiosis, when (or under what circumstances) is it advantageous to a female to reproduce via mitosis? *when there are few parasites that might attach her offspring *any situation in which it pays to produce lots of similar offspring quickly * When there is open habitat to fill quickly. * When the environment will be stable (and thus good to her genotype) 5. (2) When is it in her interest to reproduce via meiosis? * the opposite of most of the above: unpredictable environment, parasites/diseases, competition for scarce resources. When it’s advantageous to have variable offsprint. For 6-8, choose between simple dominance, incomplete dominance , and co-dominance . Given the following phenotypes for each listed genotype, identify the inheritance type represented by each (1 pt ea). 6: Incomplete dom 7: Codominance 8: Simple dominance AA Red Red Red Aa Purple Red & Blue both Red aa Blue Blue Blue 9. (2) A rooster with gray feathers mates with a hen of the same phenotype. Among their offspring, 15 chicks are gray, 6 are black, and 8 are white. What is the simplest explanation for the inheritance of these colors in chickens? Incomplete dominance (3 genotypes = 3 phenotypes; heterozygote is intermediate phenotype) with
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This note was uploaded on 04/29/2008 for the course BIO 101 taught by Professor Grinnell during the Fall '07 term at Gustavus.

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Exam_3_key - Exam 3: Bio 101 (45 pts) 14 November 2007 Name...

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