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Chapter 3 Objectives

# Chapter 3 Objectives - weight IE Formila Weight of H2SO4 =...

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Chapter 3 Objectives : Balance Chemical Equations: H_2 + O_2 = H_2 O_2 Not balanced 2 H_2 + O_2 = 2 H_2 O Now, there is 4 H’s on right and left side and 2 oxygen on right and left Reactants: starting substances ^ H and O (left hand side) Products: produced from reactants (right hand side) Combination Reaction : two or more substances react to make one product A + B C C + O2 CO2 Decomposition Reaction : one substance undergoes s reaction to produce two or more other substances C A + B 2KClO_3 2KCl + 3O_2 2NaN_3 2Na + 3N_2 Combustion Reaction :rapid reactions that produce a flame (methane experiment in class) CH_4 + 2O_2 CO_2 + 2H_2O Formula Weight: sum of the atomic weights of each atom in its chemical formula (look at periodic chart) Molecular Weight : if the formula is a molecular formula, the formula weight is called the molecular

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Unformatted text preview: weight IE. Formila Weight of H2SO4 = 2 (1.01) + 1(32.1) + 4(16.0) = 98.1 amu Percentage of an Element in a Molecule from Chemical Formula:-Percentage composition of a substance % element = (number of atoms of that element) (atomic weight of element) / formula weight of compound) X 100 IE. Percent of Carbon in C12H22O11 %C = ( 12 ) ( 12.0 amu C ) / 342.0 amu C12H22O11 ) X 100 = 42.1 % Avogrado’s Number : 6.022 X 10^23 = 1 mol Molar Mass: mass in grams of substance (g/mol) IE. Molar mass of C6H12O6 C6 = 6 * 12.0 amu = 72 H12 = 12 * 1.0 amu = 12 O6 = 6 *16.0 amu = 96.0 Then add together: 72+12+96 = 180 amu Molar Mass = 180. One mole of this substance has a mass of 180....
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Chapter 3 Objectives - weight IE Formila Weight of H2SO4 =...

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