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Exam 4 review

Exam 4 review - Exam 4 review 13 concept questions and 7...

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Exam 4 review 13 concept questions and 7 math 13 buffer and equilibrium problems and 7 Ksp Strong acids and bases- completely dissolve in water Most thing with Cl or nitrate will completely dissolve Ionization constant o Ionization constant of a weak acid Produces a proton and anion o Ka= [H][A]/[HA] o Of a weak base Kb=[HB+][OH]/[B] Hydrolysis o Conjugate base of a weak acid will undergo hydrolysis to make a basic solution A- + H2O  HA + OH- o Conjugate acid of a weak base will undergo hydrolysis to form an acidic solution o +HB  +H + B Hydrolysis Constants o KaKb =Kw for a conjugate acid-base pair o The hydrolysis constant of the conjugate base of a weak aicd is defined by Kb= [HA][OH-]/[A-] o The hydrolysis constant of the conjugate acid of a weak base is Ka= [B][+H]/[+HB] Salts in aqueous solutions o Salt of a strong base and strong acid (NaCl) Completely dissolves in water and makes a neutral solution because the conjugates don’t react o Salt of a strong base and weak acid Makes a basic solution (NaF) because the conjugate base will react with water and make OH- o Salt of a weak base and strong acid (Nhh4Cl) Makes acidic solution dissolved in water. The ammonia will donate a proton to make acidic o Salt of a weak base and weak acid (Nh4NO2) Can be neutral, basic, or acidic, depending on the Ka and Kb Neutral- only from ammonium acetate

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