tsl215 - B x = μ nI 2 R 2 Z x 2 x 1 dx x 2 R 2 3 2 = μ nI...

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Magnetic Field on the Axis of a Solenoid Number of turns per unit length: n = N/L Current circulating in ring of width dx : nIdx Magnetic field on axis of ring: dB x = μ 0 ( nIdx ) 2 R 2 ( x 2 + R 2 ) 3 / 2 Magnetic field on axis of solenoid:
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Unformatted text preview: B x = μ nI 2 R 2 Z x 2 x 1 dx ( x 2 + R 2 ) 3 / 2 = μ nI 2 x 2 p x 2 2 + R 2-x 1 p x 2 1 + R 2 ! tsl215 – p.1/1...
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