# tsl212 - E x along the axis of a charged ring and the...

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Magnetic Field Application (1) A particle with charge q = 4 . 5 nC is moving with velocity ~v = 3 × 10 3 m / s ˆ i . Find the magnetic field generated at the origin of the coordinate system. Position of field point relative to particle: ~ r = 4m ˆ i - 3m ˆ j Distance between Particle and field point: r = p (4m) 2 + (3m) 2 = 5m Magnetic field: ~ B = μ 0 4 π q~v × ˆ r r 2 = μ 0 4 π q~v × ~ r r 3 = μ 0 4 π q (3 × 10 3 m / s ˆ i ) × (4m ˆ i - 3m ˆ j ) (5m) 3 = - μ 0 4 π q (3 × 10 3 m / s ˆ i ) × (3m ˆ j ) (5m) 3 = - 3 . 24 × 10 - 14 T ˆ k. tsl212 – p.1/2

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Magnetic Field Application (11) The electric field
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Unformatted text preview: E x along the axis of a charged ring and the magnetic field B x along the axis of a circular current loop are E x = Q 4 x ( x 2 + R 2 ) 3 / 2 , B x = I 2 R 2 ( x 2 + R 2 ) 3 / 2 (a) Simplify both expressions for x = 0 . (b) Simplify both expressions for x R . (c) Sketch graphs of E x ( x ) and B x ( x ) . x B x E x x tsl228 p.2/2...
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## This note was uploaded on 04/30/2008 for the course PHYS 204 taught by Professor Andrevantonder during the Spring '07 term at Rhode Island.

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tsl212 - E x along the axis of a charged ring and the...

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