# tsl306 - RLC Parallel Circuit(1 Applied alternating voltage...

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RLC Parallel Circuit (1) Applied alternating voltage: E = E max cos ωt Resulting alternating current: I = I max cos( ωt - δ ) Goals: Find I max , δ for given E max , ω . Find currents I R , I L , I C through devices. Junction rule: I = I R + I L + I C Note: All currents are time-dependent. In general, each current has a different phase I R has the same phase as E . A A A ~ A L C R ε I L I C I I R tsl306 – p.1/3

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RLC Parallel Circuit (2) Phasor diagram (for ωt = δ ): ε I I R I I C C L I - I L δ Current amplitudes: I R,max = E max X R = E max R I L,max = E max X L = E max ωL I C,max = E max X C = E max ωC Relation between E max and I max from geometry: I 2 max = I 2 R,max + ( I L,max - I C,max ) 2 = E 2 max " 1 R 2 + 1 ωL - ωC « 2 # tsl307 – p.2/3
RLC Parallel Circuit (3) Impedance:
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tsl306 - RLC Parallel Circuit(1 Applied alternating voltage...

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