tsl309 - series circuit with inductance L = 88 m H...

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AC Circuit Application (3) Find the current amplitudes I 1 , I 2 , I 3 (a) for angular frequency ω = 2 rad/s, (b) for angular frequency ω = 4 rad/s. ~ A A A ε max =50V I 3 I 2 I 1 C=0.1F L=2.5H R=10 tsl309 – p.1/4
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AC Circuit Application (4) Given the current amplitudes I 1 , I 2 , I 3 through the three branches of this RLC circuit, and given the amplitude E max = 100 V and angular frequency ω = 500 rad/s of the ac source, find the device properties R, L, C . ~ A A A I 3 I 2 I 1 R L C =25mA =75mA =213.6mA ε tsl310 – p.2/4
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AC Circuit Application (5) Find the current amplitudes I 1 , I 2 , I 3 , I 4 in the four RLC circuits shown. ~ A ~ A ~ A ~ A =1V max ε ϖ =1rad/s 2 I 1 1F 1H =1V max ε ϖ =1rad/s 4 I =1V max ε ϖ =1rad/s 1 1H 1F 1 I 1F 1H 1 =1V max ε ϖ =1rad/s 1 3 I 1H 1F tsl312 – p.3/4
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AC Circuit Application (6) Consider an RLC
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Unformatted text preview: series circuit with inductance L = 88 m H, capacitance C = 0 . 94 μ F, and unknown resistance R . The ac generator E = E max sin( ωt ) has amplitude E max = 24 V and frequency f = 930 Hz. The phase angle is δ = 75 ◦ . (a) Find the resistance R . (b) Find the current amplitude I max . (c) Find the maximum energy U max L stored in the inductor. (d) Find the maximum energy U max C stored in the capacitor. (e) Find the time t 1 at which the current has its maximum value I max . (f) Find the time t 2 at which the charge on the capacitor has its maximum value Q max . tsl313 – p.4/4...
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This note was uploaded on 04/30/2008 for the course PHYS 204 taught by Professor Andrevantonder during the Spring '07 term at Rhode Island.

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tsl309 - series circuit with inductance L = 88 m H...

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