tsl129 - 1 C = 1 C 1 1 C 2 with C 1 = κ 1 ² A d 2 C 2 =...

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Stacked Dielectrics Consider a parallel-plate capacitor with area A of each plate and spacing d . Capacitance without dielectric: C 0 = ² 0 A d . Dielectrics stacked in parallel: C = C 1 + C 2 with C 1 = κ 1 ² 0 A/ 2 d , C 2 = κ 2 ² 0 A/ 2 d . C = 1 2 ( κ 1 + κ 2 ) C 0 . Dielectrics stacked in series:
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Unformatted text preview: 1 C = 1 C 1 + 1 C 2 with C 1 = κ 1 ² A d/ 2 , C 2 = κ 2 ² A d/ 2 ⇒ C = 2 κ 1 κ 2 κ 1 + κ 2 C . tsl129 – p.1/1...
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This note was uploaded on 04/30/2008 for the course PHYS 204 taught by Professor Andrevantonder during the Spring '07 term at Rhode Island.

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