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Unformatted text preview: (b) What is the electric flux E through the door opened at = 90 ? (c) At what angle 1 is the electric flux through the door zero? (d) At what angle 2 is the electric flux through the door a maximum? tsl42 p.3/4 Electric Flux: Application (4) Consider a positive point charge Q at the center of a spherical surface of radius R . Calculate the electric flux through the surface. ~ E is directed radially outward. Hence ~ E is parallel to d ~ A everywhere on the surface. ~ E has the same magnitude, E = kQ/R 2 , everywhere on the surface. The area of the spherical surface is A = 4 R 2 . Hence the electric flux is E = EA = 4 kQ . Note that E is independent of R . tsl43 p.4/4...
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This note was uploaded on 04/30/2008 for the course PHYS 204 taught by Professor Andrevantonder during the Spring '07 term at Rhode Island.
 Spring '07
 AndrevanTonder

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