tsl161 - Loop B (ccw): (3) I 2 + 1V + (2) I 2-6V = 0...

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Applying Kirchhoff’s Rules Consider the circuit shown below. Junction a : I 1 , I 2 (in); I 1 + I 2 (out) Junction b : I 1 + I 2 (in); I 1 , I 2 (out) Two independent currents require the use of two loops. Loop A (ccw): 6V - (2Ω) I 1 - 2V - (2Ω) I 1 = 0
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Unformatted text preview: Loop B (ccw): (3) I 2 + 1V + (2) I 2-6V = 0 Solution: I 1 = 1A , I 2 = 1A I 2 1 A 2V 6V 2 1 I 2 b a I + I I + I 1 2 B 2 2 I 1 I 2 3 1V tsl161 p.1/1...
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