HW7_Solutions

# HW7_Solutions - DEC-EE-EE’IES 13 34 F[le Chapter7 15.01...

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Unformatted text preview: DEC-EE-EE’IES 13: 34 F' . [le Chapter7 15. .01 I7. X;st ‘- 10. 11:35:11 2:. i=i=3'1=1.55 2 .2 2):", 2X3 20.3inceMl:’=‘ =M=192 and M2="=‘ =§E§=3031 H 15 H 15 ‘ . MFMIZ 393141.92)2 =—m-=—m—_—=.1279 ﬂ M, 1.92 ci=wi=ﬂ=150117 ,6 .1279. 0 =00 =(15.0117)(.1279)=1.92 &2 = M2 —M3 :3..C.I32#(1.02)2 12450 27. (a) 31 9 32 0 3 5 33 ( 33 9 34 0 35 0 (b) 333.8: 00.85 (c) 62.94 33. (a) £12 A (b) X = 213: yes (a) 35.25 (:1) 70.5 - 35. .1 4'7. (01) .643 (b) .643 :t .0039 (c) shorter; .643 :r .0033 (ii) longﬂ; .643 i .0052 DEC-EE-EEES 13:35 P 82 43. (a) Using the method described in Exercise 27 of this chapter, 0 3 0 87997 1 2441144332433141 _ 1 689658663665565 2 010 t yes if (b) i=%=13.85 days . f 4 o 13.85i1.96 — =13.85i1.2396 ” * [42s] We are 95% confident that the interval (12.6 days, 15.1 days) will contain ,u . yes, I would be surprised to hear a claim that #:17 days since we are only 2.5% sure that ,u is 15.1 days 52. (a) 913. i (b) 2X; yes (a) 2.06 1 59. (a) gamma with o: 2 and [3 = B (b) 20 . (c) 3/2 7 (d) X12; no ‘ _ = (e) 1.55 i m YES i TDTRL P.82 ...
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